Review Quiz - 3rd Qtr

$$\left(-5\right)^2=\left(-5\right)\left(-5\right)=25$$

negative x negative = positive

$$\sqrt[5]{175}$$

base = 175

exponent = 1

index = 5

$$\left(base\right)^{\frac{\exp onent}{index}}=175^{\frac{1}{5}}$$

$$\sqrt[]{x+2}=\sqrt[]{2x-1}$$

square both sides to cancel square root

$$\left(\sqrt[]{x+2}\right)^2=\left(\sqrt[]{2x-1}\right)^2$$

$$x+2=2x-1$$

transpose to combine like terms (change sign)

$$2+1=2x-x$$

$$3=x$$

square root of thrice a number = 9

$$\sqrt[]{3x}=9$$

(square both sides to remove radical sign)

$$\left(\sqrt[]{3x}\right)^2=\left(9\right)^2$$

$$3x=81$$

divide both sides by 3

$$\frac{3x}{3}=\frac{81}{3}$$

$$x=27$$