ÔN TẬP GIỮA KÌ II TOÁN 12

$$\frac{11}{3}$$

$$\frac{14}{3}$$

$$\frac{5}{3}$$

$$-\frac{22}{3}$$

$$I\left(1;-1;2\right),R=2$$

$$I\left(1;-1;2\right),R=\sqrt[]{5}$$

$$I\left(1;-1;2\right),R=\sqrt[]{6}$$

$$I\left(1;1;2\right),R=\sqrt[]{5}$$

(1;1;1)

(-1;1;- 1)

(1;-1;1)

(-1; -1; -1)

$$\int_a^af\left(x\right)dx=0$$

$$\int_a^bf\left(x\right)dx=\int_b^af\left(x\right)dx$$

$$\int_a^bkf\left(x\right)dx=k\int_a^bf\left(x\right)dx$$ k là hằng số

$$\int_a^b1dx=b-a$$

$$x+2e^x+e_{ }^{2x}+C$$

$$x+2e^x+\frac{1}{2}e_{ }^{2x}+C$$

$$x+2e^x-\frac{1}{2}e_{ }^{2x}+C$$

$$1+e^x+e_{ }^{2x}+C$$

$$\frac{1}{2}\ln\left(2x-1\right)+C$$

$$\frac{1}{2}\ln\left|2x-1\right|+C$$

$$2\ln\left|2x-1\right|+C$$

$$-\frac{1}{2}\ln\left|2x-1\right|+C$$

f'(x) = F(x), $$\forall x\in K$$

F(x) = f(x),

$$\forall x\in K$$

F'(x) = f(x),

$$\forall x\in K$$

F'(x) = f'(x), $$\forall x\in K$$

$$\int f'\left(x\right)dx=f\left(x\right)+C,C\in R$$

$$\int f\left(x\right)dx=f^2\left(x\right)+C,C\in R$$

$$\int f\left(x\right)dx=f'\left(x\right)+C,C\in R$$

$$\int f'\left(x\right)dx=f'\left(x\right)+C,C\in R$$

$$\frac{\sin^2x}{2}+C$$

$$-\frac{\sin^2x}{2}+C$$

$$\sin^2x+C$$

$$\sin2x+C$$