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Identities, Trigonometric equations and Vectors REvision

Authored by Ahmad Elhajj

Mathematics, Other

11th Grade

Used 2+ times

Identities, Trigonometric equations and Vectors REvision
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22 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Write as a single expression sin⁡75ocos⁡15o−cos⁡75o sin⁡15o\sin75^o\cos15^o-\cos75^{o\ }\sin15^o  

sin⁡ 90o \sin\ 90^{o\ }  

sin⁡ 60o \sin\ 60^{o\ }  

cos⁡ 90o \cos\ 90^{o\ }  

cos⁡ 60o \cos\ 60^{o\ }  

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Write as a single expression 1−2sin⁡250o1-2\sin^250^o  

2sin⁡ 100o 2\sin\ 100^{o\ }  

sin⁡2 50o \sin^2\ 50^{o\ }  

cos⁡2100o \cos^2100^{o\ }  

cos⁡100o \cos100^{o\ }  

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Write as a single expression
cos⁡(π3)cos⁡(2π5)−sin⁡(π3)sin⁡(2π5)\cos\left(\frac{\pi}{3}\right)\cos\left(\frac{2\pi}{5}\right)-\sin\left(\frac{\pi}{3}\right)\sin\left(\frac{2\pi}{5}\right)


sin⁡(11π5)\sin\left(\frac{11\pi}{5}\right)

cos⁡(11π5)\cos\left(\frac{11\pi}{5}\right)

sin⁡(π15)\sin\left(\frac{\pi}{15}\right)

cos⁡(π15)\cos\left(\frac{\pi}{15}\right)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

tan⁡45o+tan⁡30o1−tan⁡45otan⁡30o\frac{\tan45^o+\tan30^o}{1-\tan45^o\tan30^o}  is equivalent to

tan⁡75o\tan75^o  

tan⁡ 15o\tan\ 15^o  

sin⁡45ocos⁡30o\frac{\sin45^o}{\cos30^o}  

tan⁡90o \tan90^{o\ }  

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Use sum or difference angles identity to find the exact value for cos⁡105o\cos105^o  

6+24\frac{\sqrt{6}+\sqrt{2}}{4}  

6−24\frac{\sqrt{6}-\sqrt{2}}{4}  

−6−24\frac{-\sqrt{6}-\sqrt{2}}{4}  

2−64\frac{\sqrt{2}-\sqrt{6}}{4}  

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Use sum or difference angle's identity to find the exact value for  sin⁡ (15o)\sin\ \left(15^o\right)  

6+24\frac{\sqrt{6}+\sqrt{2}}{4}  

6−24\frac{\sqrt{6}-\sqrt{2}}{4}  

2−64\frac{\sqrt{2}-\sqrt{6}}{4}  

−32-\frac{\sqrt{3}}{2}  

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given sin⁡x=35\sin x=\frac{3}{5}  where x is an acute angle. Evaluate cos⁡(π6+x)Evaluate\ \cos\left(\frac{\pi}{6}+x\right)  

43+310\frac{4\sqrt{3}+3}{10}  

43−310\frac{4\sqrt{3}-3}{10}

25+1215\frac{2\sqrt{5}+12}{15}  

45+25\frac{4\sqrt{5}+2}{5}  

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