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TEST DE EVALUARE_V_CE_TULCEA_23.12.2023

Authored by SANDA BARBU

Mathematics

5th Grade

Used 6+ times

TEST DE EVALUARE_V_CE_TULCEA_23.12.2023
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17 questions

Show all answers

1.

DROPDOWN QUESTION

3 mins • 1 pt

Dacă a=270a=2^{70} și b=342b=3^{42} , atunci:​ (a)  

a>ba>b  

a=ba=b
a<ba<b
a−b=128a-b=1^{28}

2.

DRAG AND DROP QUESTION

5 mins • 1 pt

Dacă abc‾\overline{abc} , acb‾\overline{acb} şi cba‾\overline{cba} sunt pătrate perfecte, atunci suma sau produsul cifrelor numerelor de forma abc‾\overline{abc} este:​ (a)  

1616  

1010
1212
1414

3.

DROPDOWN QUESTION

3 mins • 1 pt

Dacă a+3b=427a+3b=427 şi 2b+3c=2322b+3c=232 , atunci 2a+16b+15c2a+16b+15c are valoarea:​ (a)  

20142014  

20132013
20232023
20242024

4.

DROPDOWN QUESTION

3 mins • 1 pt

Suma numerelor naturale de forma ab‾\overline{ab} care verifică egalitatea ab‾+ba‾=55\overline{ab}+\overline{ba}=55 ​ (a)   este:

160160  

9696
201201
110110

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Restul obţinut prin împărţirea numărului N=1⋅2⋅3⋅...⋅20+2012N=1\cdot2\cdot3\cdot...\cdot20+2012 la 85 este:

5757

2323

8585

55

6.

DROPDOWN QUESTION

3 mins • 1 pt

Rezultatul calculului (2n+3⋅3n+2n⋅3n+1+6n):6n\left(2^{n+3}\cdot3^n+2^n\cdot3^{n+1}+6^n\right):6^n ​ (a)   este:

1212  

3n3^n
1111
88

7.

DROPDOWN QUESTION

5 mins • 1 pt

Suma a trei numere naturale consecutive este 320123^{2012} .

Ultima cifră a produsului celor trei numere este :​ (a)  

66  

22
44
88

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