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Тотожні перетворення раціональних дробів

Authored by Ірина Карпець

Mathematics

8th Grade

Used 1+ times

Тотожні перетворення раціональних дробів
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12 questions

Show all answers

1.

MULTIPLE SELECT QUESTION

20 sec • 1 pt

Виберіть вирази , які є дробовими

х+у2\frac{х+у}{2}

аса+с\frac{ас}{а+с}

х2+у22ху\frac{х^2+у^2}{2ху}

Answer explanation

Дробовими є вирази: \(\frac{ас}{а+с}\) та \(\frac{х^2+у^2}{2ху}\), оскільки вони містять дробові числа.

2.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Знайдіть значення виразу

х2−9х+3\frac{х^2-9}{х+3}   при х=3,2

4

0,2

6.2

Answer explanation

To find the value of the expression, substitute x=3.2 into the expression. The correct choice, 0.2, is obtained by evaluating the expression.

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

3a2a−10\frac{3a}{2a-10}  При якому значенні змінної не має змісту вираз

5

-5

5 і -5

0

Answer explanation

The expression does not have meaning when the variable is equal to 5.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Скоротіь дріб −14cd49c\frac{-14cd}{49c}

−2d7\frac{-2d}{7}

−2d7c\frac{-2d}{7c}

2d7\frac{2d}{7}

−2d27\frac{-2d^2}{7}

Answer explanation

The correct choice is −2d7\frac{-2d}{7} because it simplifies the given fraction.

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

5a−20a2 −16\frac{5a-20}{a^2\ -16}  Скоротіть дріб:

a +4a\ +4  

a−4a-4  

5a−4\frac{5}{a-4}  

5a+4\frac{5}{a+4}  

Answer explanation

To simplify the fraction, factor the numerator and denominator. The common factor of 5 can be canceled out, leaving 1 in the numerator. The simplified fraction is 1/(a+4), which matches the correct choice.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Спростіть вираз bx−23x\frac{b}{x}-\frac{2}{3x}

3b−23x\frac{3b-2}{3x}

3b+23x\frac{3b+2}{3x}

3b−24x\frac{3b-2}{4x}

b−23x\frac{b-2}{3x}

Answer explanation

The expression can be simplified to (3b-2)/(3x). This is the correct choice because it combines the fractions and simplifies the numerator and denominator.

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

a2a2−9 −aa+3\frac{a^2}{a^2-9}\ -\frac{a}{a+3}  

3aa2−9\frac{3a}{a^2-9}  

−3aa2−9-\frac{3a}{a^2-9}  

2a2−3aa2−9\frac{2a^2-3a}{a^2-9}  

1a2−9\frac{1}{a^2-9}  

Answer explanation

The correct choice is because it simplifies the given expression correctly.

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