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Att skapa andragardsfunktionsuttryck utifrån graf

Authored by Svetlana Yushmanova

Mathematics

10th Grade

Used 2+ times

Att skapa andragardsfunktionsuttryck utifrån graf
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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

f(x)=a⋅ (x−x1)(x−x2)f\left(x\right)=a\cdot\ \left(x-x_1\right)\left(x-x_2\right)

I detta fallet är a=1 så den behöver du inte bry dig om just nu.

f(x)=(x+3)(x−1)f\left(x\right)=\left(x+3\right)\left(x-1\right)

f(x)=(x−3)(x+1)f\left(x\right)=\left(x-3\right)\left(x+1\right)

f(x)=(x−3)(x−1)f\left(x\right)=\left(x-3\right)\left(x-1\right)

f(x)=(x+3)(x+1)f\left(x\right)=\left(x+3\right)\left(x+1\right)

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

f(x)=a⋅ (x−x1)(x−x2)f\left(x\right)=a\cdot\ \left(x-x_1\right)\left(x-x_2\right)

I detta fallet är a=1 så den behöver du inte bry dig om just nu.

f(x)=(x+3)(x−1)f\left(x\right)=\left(x+3\right)\left(x-1\right)

f(x)=(x−3)(x+1)f\left(x\right)=\left(x-3\right)\left(x+1\right)

f(x)=(x−3)(x−1)f\left(x\right)=\left(x-3\right)\left(x-1\right)

f(x)=(x+3)(x+1)f\left(x\right)=\left(x+3\right)\left(x+1\right)

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

f(x)=a⋅ (x−x1)(x−x2)f\left(x\right)=a\cdot\ \left(x-x_1\right)\left(x-x_2\right)

I detta fallet är a=1 så den behöver du inte bry dig om just nu.

f(x)=(x+3)(x−1)f\left(x\right)=\left(x+3\right)\left(x-1\right)

f(x)=(x−3)(x+1)f\left(x\right)=\left(x-3\right)\left(x+1\right)

f(x)=(x−3)(x−1)f\left(x\right)=\left(x-3\right)\left(x-1\right)

f(x)=(x+3)(x+1)f\left(x\right)=\left(x+3\right)\left(x+1\right)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

f(x)=a⋅ (x−x1)(x−x2)f\left(x\right)=a\cdot\ \left(x-x_1\right)\left(x-x_2\right)

Nu behöver du även räkna ut vad a är, använd en valfri punkt på kurvan

f(x)=−2(x−3)(x+1)f\left(x\right)=-2\left(x-3\right)\left(x+1\right)

f(x)=−(x−3)(x+1)f\left(x\right)=-\left(x-3\right)\left(x+1\right)

f(x)=−12(x−3)(x+1)f\left(x\right)=-\frac{1}{2}\left(x-3\right)\left(x+1\right)

f(x)=−3(x−3)(x+1)f\left(x\right)=-3\left(x-3\right)\left(x+1\right)

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

f(x)=a⋅ (x−x1)(x−x2)f\left(x\right)=a\cdot\ \left(x-x_1\right)\left(x-x_2\right)

Nu behöver du även räkna ut vad a är, använd en valfri punkt på kurvan

f(x)=2(x+1)f\left(x\right)=2\left(x+1\right)

f(x)=2(x+1)2f\left(x\right)=2\left(x+1\right)^2

f(x)=12(x+1)2f\left(x\right)=\frac{1}{2}\left(x+1\right)^2

f(x)=2(x−1)2f\left(x\right)=2\left(x-1\right)^2

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

f(x)=a(x−xsym)2+ymin⁡ max⁡f\left(x\right)=a\left(x-x_{sym}\right)^2+y_{\min\ \max}

Här är det a=1 så den behöver du inte bry dig om

f(x)=(x−2)2−3f\left(x\right)=\left(x-2\right)^2-3

f(x)=(x−3)2−2f\left(x\right)=\left(x-3\right)^2-2

f(x)=(x+2)2−3f\left(x\right)=\left(x+2\right)^2-3

f(x)=(x−2)2+3f\left(x\right)=\left(x-2\right)^2+3

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

f(x)=a(x−xsym)2+ymin⁡ max⁡f\left(x\right)=a\left(x-x_{sym}\right)^2+y_{\min\ \max}

Här är det a=1 så den behöver du inte bry dig om

f(x)=(x−2)2−3f\left(x\right)=\left(x-2\right)^2-3

f(x)=(x−3)2−2f\left(x\right)=\left(x-3\right)^2-2

f(x)=(x+2)2−3f\left(x\right)=\left(x+2\right)^2-3

f(x)=(x−2)2+3f\left(x\right)=\left(x-2\right)^2+3

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