PA Alg1 Keystone Review Module 1

$$\sqrt[]{13}=3.606$$

$$\sqrt[]{17}=4.123$$

$$\sqrt[]{22}=4.690$$

$$\sqrt[]{28}=5.292$$

$$\sqrt[]{54}$$

$$\sqrt[]{9}\cdot\sqrt[]{6}$$

$$3\cdot\sqrt[]{6}$$

$$3\sqrt[]{6}$$

$$a\cdot a\cdot b\cdot b\cdot b\cdot b\cdot b$$

$$a\cdot a\cdot a\cdot b\cdot b\cdot b$$

2 a's are in common and 3 b's are in common. That means our final answer should be $$a^2b^3$$

We take the highest exponent of each variable and then look for the smallest multiple of the numbers.

Between 100 and 60, 300 is the smallest multiple.

$$\left|-14+6-12\right|$$

$$\left|-8-12\right|$$

$$\left|-20\right|$$

$$20$$

$$\frac{2^7\cdot2^5}{2^p}=\frac{2^{12}}{2^p}=2^3$$

12-p=3

-12 -12

-p=-9

p=9

$$\sqrt[]{4}\cdot\sqrt[]{a^8}\cdot\sqrt[]{b^2}$$

$$2\cdot a^4\cdot b$$