Jika diketahui maka carilah nilai z 1 - 5z 2 dan -2z 1/ z 2 Hasilnya

– ( 18 + 22 i ) d a n − 46 − 4 i 41 –(18+22i)\ dan\frac{-46-4i}{41} – ( 1 8 + 2 2 i ) d a n 4 1 − 4 6 − 4 i

– ( 18 − 22 i ) d a n 46 − 4 i 41 –(18-22i)\ dan\frac{46-4i}{41} – ( 1 8 − 2 2 i ) d a n 4 1 4 6 − 4 i

18 + 22 i d a n − 46 + 4 i 41 18+22i\ dan\frac{-46+4i}{41} 1 8 + 2 2 i d a n 4 1 − 4 6 + 4 i

18 − 22 i d a n 46 + 4 i 41 18-22i\ dan\frac{46+4i}{41} 1 8 − 2 2 i d a n 4 1 4 6 + 4 i

Nyatakan bilangan kompleks z = 2 -2i dalam bentuk polar dan eksponen !

z = 2 2 ( C o s 7 4 π + i S i n 7 4 π ) , z = 2 2 e 7 π 4 i z=2\sqrt{2}\left(Cos\ \frac{7}{4}\pi+i\ Sin\ \frac{7}{4}\pi\right),\ \ z=2\sqrt{2}e^{\frac{7\pi}{4}i} z = 2 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> ( C o s 4 7 π + i S i n 4 7 π ) , z = 2 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> e 4 7 π i

z = 2 2 ( C o s 5 4 π + i S i n 5 4 π ) , z = 2 2 e 5 π 4 i z=2\sqrt{2}\left(Cos\ \frac{5}{4}\pi+i\ Sin\ \frac{5}{4}\pi\right),\ \ z=2\sqrt{2}e^{\frac{5\pi}{4}i} z = 2 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> ( C o s 4 5 π + i S i n 4 5 π ) , z = 2 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> e 4 5 π i

z = 2 ( C o s 5 4 π + i S i n 5 4 π ) , z = 2 e 5 π 4 i z=\sqrt{2}\left(Cos\ \frac{5}{4}\pi+i\ Sin\ \frac{5}{4}\pi\right),\ \ z=\sqrt{2}e^{\frac{5\pi}{4}i} z = 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> ( C o s 4 5 π + i S i n 4 5 π ) , z = 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> e 4 5 π i

z = 2 ( C o s 7 4 π + i S i n 7 4 π ) , z = 2 e 7 π 4 i z=\sqrt{2}\left(Cos\ \frac{7}{4}\pi+i\ Sin\ \frac{7}{4}\pi\right),\ \ z=\sqrt{2}e^{\frac{7\pi}{4}i} z = 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> ( C o s 4 7 π + i S i n 4 7 π ) , z = 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> e 4 7 π i

N i l a i d a r i 3 + 2 3 = . . . . Nilai\ dari\ \ \sqrt{3}\ +\ 2\sqrt{3}=.... N i l a i d a r i 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> + 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> = . . . .

3 3 3\sqrt{3} 3 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 3 1\sqrt{3} 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 3 2\sqrt{3} 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

4 3 4\sqrt{3} 4 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

5 3 5\sqrt{3} 5 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Bilangan Kompleks

Authored by Nesy Widyastuti

Mathematics

University

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FILL IN THE BLANKS QUESTION

30 sec • 1 pt

Notasi selang untuk himpunan $\left\{x\left|2\le x<5\right|\right\}$ adalah...

(a)

MULTIPLE SELECT QUESTION

30 sec • 1 pt

Garis bilangan yang tepat untuk menyatakan selang (4, 7] adalah ...

MULTIPLE SELECT QUESTION

30 sec • 1 pt

Yang tidak termasuk bilangan rasional adalah ...

0,8

$\frac{3}{5}$

2,783

4,5676767...

$\sqrt{5}$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$tentukan\ nilai\ dari$
$\frac{1}{2}+\ \frac{3}{2}\ =\ ....$

$\frac{2}{6}$

$\frac{3}{4}$

$\frac{2}{4}$

$\frac{3}{2}$

$\frac{4}{2}$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Hasil dari (9x^-2 y³ z^-4)²adalah....

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Jumlah baris ke-9 pada segitiga pascal adalah ....

512

256

900

128

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Suku ke-20 dari barisan bilangan Aritmetika
50, 46, 42, 38, 34, ...
adalah ....

-26

-18

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Nyatakan bilangan kompleks z = 1 + i dalam bentuk polar dan eksponen !

$z=\sqrt{2}\left(Cos\ \frac{1}{4}\pi+i\ Sin\ \frac{1}{4}\pi\right),\ \ z=\sqrt{2}e^{\frac{\pi}{4}i}$

$z=\sqrt{2}\left(Cos\ \frac{1}{2}\pi+i\ Sin\ \frac{1}{2}\pi\right),\ \ z=\sqrt{2}e^{\frac{\pi}{2}i}$

$z=\sqrt{2}\left(Cos\ \frac{3}{4}\pi+i\ Sin\ \frac{3}{4}\pi\right),\ \ z=\sqrt{2}e^{\frac{3\pi}{4}i}$

$z=\sqrt{2}\left(Cos\ \pi+i\ Sin\ \pi\right),\ \ z=\sqrt{2}e^{\pi i}$

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Bilangan Kompleks

Notasi selang untuk himpunan $\left\{x\left|2\le x<5\right|\right\}$ adalah...

(a)

Garis bilangan yang tepat untuk menyatakan selang (4, 7] adalah ...

Yang tidak termasuk bilangan rasional adalah ...

$tentukan\ nilai\ dari$
$\frac{1}{2}+\ \frac{3}{2}\ =\ ....$

Hasil dari (9x^-2 y³ z^-4)²adalah....

Jumlah baris ke-9 pada segitiga pascal adalah ....

Suku ke-20 dari barisan bilangan Aritmetika
50, 46, 42, 38, 34, ...
adalah ....

Nyatakan bilangan kompleks z = 1 + i dalam bentuk polar dan eksponen !

Harga Es krim di supermarket 7.525, sedangkan di penjual kelilig hanya 7.200 berapakah selisih harganya?

Tentukan hasil dari 3+5x2-10:2

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Popular Resources on Wayground

Bilangan Kompleks

Notasi selang untuk himpunan {x∣2≤x<5∣}\left\{x\left|2\le x<5\right|\right\}{x∣2≤x<5∣} adalah... (a)

Garis bilangan yang tepat untuk menyatakan selang (4, 7] adalah ...

Yang tidak termasuk bilangan rasional adalah ...

tentukan nilai daritentukan\ nilai\ daritentukan nilai dari 12+ 32 = ....\frac{1}{2}+\ \frac{3}{2}\ =\ ....21​+ 23​ = ....

Hasil dari (9x-2 y3 z-4 )2 adalah....

Jumlah baris ke-9 pada segitiga pascal adalah ....

Suku ke-20 dari barisan bilangan Aritmetika50, 46, 42, 38, 34, ...adalah ....

Nyatakan bilangan kompleks z = 1 + i dalam bentuk polar dan eksponen !

Harga Es krim di supermarket 7.525, sedangkan di penjual kelilig hanya 7.200 berapakah selisih harganya?

Tentukan hasil dari 3+5x2-10:2

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Notasi selang untuk himpunan $\left\{x\left|2\le x<5\right|\right\}$ adalah...

(a)

$tentukan\ nilai\ dari$
$\frac{1}{2}+\ \frac{3}{2}\ =\ ....$

Hasil dari (9x^-2 y³ z^-4)²adalah....

Suku ke-20 dari barisan bilangan Aritmetika
50, 46, 42, 38, 34, ...
adalah ....