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Daugybos skirstomumo dėsnis

Authored by Jolanta Jankauskienė

Mathematics

5th Grade

Used 15+ times

Daugybos skirstomumo dėsnis
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15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

(14+5)×4\left(14+5\right)\times4 pritaikę daugybos skirstomumo dėsnį gausime

14×5+14×414\times5+14\times4

14×4+5×414\times4+5\times4

14×5+14×414\times5+14\times4

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Kuris dėsnis vadinamas daugybos skirstomumo dėsniu?

a+b=b+aa+b=b+a

a×b=b×aa\times b=b\times a

(a×b)×c=a×(b×c)\left(a\times b\right)\times c=a\times\left(b\times c\right)

(a+b)×c=a×c+b×c\left(a+b\right)\times c=a\times c+b\times c

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Ką reikia įrašyti vietoje daugtaškio (12+25)×3=12×...+25×3\left(12+25\right)\times3=12\times...+25\times3 ?

12

25

3

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Ką reikia įrašyti vietoje daugtaškio (25−8)×5=...×5−8×5\left(25-8\right)\times5=...\times5-8\times5

25

8

5

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Kokį ženklą reikia įrašyti vietoje daugtaškio (27+6)×5   ...  27×5 + 6×5\left(27+6\right)\times5\ \ \ ...\ \ 27\times5\ +\ 6\times5

>

<

=

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Apskaičiuokite: (25+11)×4=\left(25+11\right)\times4=

100

120

144

150

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Kaip galime lengviau apskaičiuoti sandaugą 5×495\times49 ?

5×(40+8)5\times\left(40+8\right)

5×(50−1)5\times\left(50-1\right)

5×40×95\times40\times9

4×49+14\times49+1

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