Điều kiện để biểu thức 1 2019 − x \sqrt{\frac{1}{2019-x}} 2 0 1 9 − x 1 <path d="M424,2478c-1.3,-0.7,-38.5,-172,-111.5,-514c-73, -342,-109.8,-513.3,-110.5,-514c0,-2,-10.7,14.3,-32,49c-4.7,7.3,-9.8,15.7,-15.5, 25c-5.7,9.3,-9.8,16,-12.5,20s-5,7,-5,7c-4,-3.3,-8.3,-7.7,-13,-13s-13,-13,-13, -13s76,-122,76,-122s77,-121,77,-121s209,968,209,968c0,-2,84.7,-361.7,254,-1079 c169.3,-717.3,254.7,-1077.7,256,-1081c4,-6.7,10,-10,18,-10H400000v40H1014.6 s-87.3,378.7,-272.6,1166c-185.3,787.3,-279.3,1182.3,-282,1185c-2,6,-10,9,-24,9 c-8,0,-12,-0.7,-12,-2z M1001 80H400000v40H1014z"> có nghĩa là:

x ≠ 2019 x\ne2019 x  = 2 0 1 9

x ≥ 2019 x\ge2019 x ≥ 2 0 1 9

x ≤ 2019 x\le2019 x ≤ 2 0 1 9

Tìm x biết: x − 1 < 2 \sqrt{x-1}<2 x − 1 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> < 2 được kết quả là:

1 ≤ x < 5 1\le x<5 1 ≤ x < 5

1 ≤ x < 3 1\le x<3 1 ≤ x < 3

Rút gọn 4 − 2 3 \sqrt{4-2\sqrt{3}} 4 − 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> <path d="M1001,80H400000v40H1013.1s-83.4,268,-264.1,840c-180.7, 572,-277,876.3,-289,913c-4.7,4.7,-12.7,7,-24,7s-12,0,-12,0c-1.3,-3.3,-3.7,-11.7, -7,-25c-35.3,-125.3,-106.7,-373.3,-214,-744c-10,12,-21,25,-33,39s-32,39,-32,39 c-6,-5.3,-15,-14,-27,-26s25,-30,25,-30c26.7,-32.7,52,-63,76,-91s52,-60,52,-60 s208,722,208,722c56,-175.3,126.3,-397.3,211,-666c84.7,-268.7,153.8,-488.2,207.5, -658.5c53.7,-170.3,84.5,-266.8,92.5,-289.5c4,-6.7,10,-10,18,-10z M1001 80H400000v40H1013z"> ta được kết quả

3 − 1 \sqrt{3}-1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 1

2 − 3 2-\sqrt{3} 2 − 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 − 2 \sqrt{3}-2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 2

1 − 3 1-\sqrt{3} 1 − 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Trong các hàm số sau hàm số nào là hàm số bậc nhất

2 x − 3 y = 5 2x-3y=5 2 x − 3 y = 5

y = 1 x + 3 y=\frac{1}{x}+3 y = x 1 + 3

2 y = x + 4 \frac{2}{y}=x+4 y 2 = x + 4

y = 2 ( x + 1 ) − 2 x y=2\left(x+1\right)-2x y = 2 ( x + 1 ) − 2 x

Cho hàm số f ( x ) = − x 2 + 3 f\left(x\right)=\frac{-x}{2}+3 f ( x ) = 2 − x + 3 . Câu nào sau đây sai?

f ( 3 ) = 3 f\left(3\right)=3 f ( 3 ) = 3

f ( − 2 ) = 4 f\left(-2\right)=4 f ( − 2 ) = 4

f ( 1 ) = 5 2 f\left(1\right)=\frac{5}{2} f ( 1 ) = 2 5

f ( 4 ) = 1 f\left(4\right)=1 f ( 4 ) = 1

Toán 9 buổi 3 (Giữa kì 1): bài tập trắc nghiệm 18 câu

18 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Điều kiện để biểu thức $\sqrt{\frac{1}{2019-x}}$ có nghĩa là:

$x\ne2019$

$x\ge2019$

$x<2019$

$x\le2019$

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Căn bậc hai số học của 4 là:
A. + 2 B. - 2 C. ± 2 D. 8.

+2

-2

$\pm2$

16

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Tìm x biết: $\sqrt{x-1}<2$ được kết quả là:

x < 5

x < 3

$1\le x<3$

$1\le x<5$

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Chiều cao của một cây cổ thụ có bóng trên mặt đất dài 4m và có tia sáng từ đỉnh tạo với mặt đất một góc bằng 60 độ là:

$3\sqrt{3}$

$4\sqrt{3}$

$\frac{4\sqrt{3}}{3}$

$6\sqrt{3}$

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Biểu thức $\sqrt{\left(\sqrt{5}-3\right)^2}-\sqrt{5}$ có kết quả là:

$3+2\sqrt{5}$

$3-2\sqrt{5}$

$2-3\sqrt{5}$

-3

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Tam giác ABC vuông tại A (AB < AC) , BC = 25 cm, đường cao AH = 12 cm. Độ dài HC bằng :

9

5,76

15

16

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Cho tam giác DEF vuông tại D , đường cao DH thì DH² bằng

FH.EF

HE.HF

EH.EF

DF.EF

8.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Cho tam giác ABC vuông tại A, có $\frac{AB}{AC}=\frac{5}{6}$ và đường cao AH = 30 cm.độ dài BH là

30

12

36

25

9.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Rút gọn $\sqrt{4-2\sqrt{3}}$ ta được kết quả

$2-\sqrt{3}$

$\sqrt{3}-2$

$1-\sqrt{3}$

$\sqrt{3}-1$

10.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Giá trị của biểu thức $P=\frac{1}{2+\sqrt{3}}+\frac{1}{2-\sqrt{3}}$ bằng

1

4

-4

$\frac{1}{2}$

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Toán 9 buổi 3 (Giữa kì 1)

Điều kiện để biểu thức 12019−x\sqrt{\frac{1}{2019-x}}2019−x1​​ có nghĩa là:

Căn bậc hai số học của 4 là: A. + 2 B. - 2 C. ± 2 D. 8.

Tìm x biết: x−1<2\sqrt{x-1}<2x−1​<2 được kết quả là:

Chiều cao của một cây cổ thụ có bóng trên mặt đất dài 4m và có tia sáng từ đỉnh tạo với mặt đất một góc bằng 60 độ là:

Biểu thức (5−3)2−5\sqrt{\left(\sqrt{5}-3\right)^2}-\sqrt{5}(5​−3)2​−5​ có kết quả là:

Tam giác ABC vuông tại A (AB < AC) , BC = 25 cm, đường cao AH = 12 cm. Độ dài HC bằng :

Cho tam giác DEF vuông tại D , đường cao DH thì DH2 bằng

Cho tam giác ABC vuông tại A, có ABAC=56\frac{AB}{AC}=\frac{5}{6}ACAB​=65​ và đường cao AH = 30 cm.độ dài BH là

Rút gọn 4−23\sqrt{4-2\sqrt{3}}4−23​​ ta được kết quả

Giá trị của biểu thức P=12+3+12−3P=\frac{1}{2+\sqrt{3}}+\frac{1}{2-\sqrt{3}}P=2+3​1​+2−3​1​ bằng

Access all questions and much more by creating a free account

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Popular Resources on Wayground

Discover more resources for Mathematics

Điều kiện để biểu thức $\sqrt{\frac{1}{2019-x}}$ có nghĩa là:

Căn bậc hai số học của 4 là:
A. + 2 B. - 2 C. ± 2 D. 8.

Tìm x biết: $\sqrt{x-1}<2$ được kết quả là:

Biểu thức $\sqrt{\left(\sqrt{5}-3\right)^2}-\sqrt{5}$ có kết quả là:

Cho tam giác DEF vuông tại D , đường cao DH thì DH² bằng

Cho tam giác ABC vuông tại A, có $\frac{AB}{AC}=\frac{5}{6}$ và đường cao AH = 30 cm.độ dài BH là

Rút gọn $\sqrt{4-2\sqrt{3}}$ ta được kết quả

Giá trị của biểu thức $P=\frac{1}{2+\sqrt{3}}+\frac{1}{2-\sqrt{3}}$ bằng