3-1圓的方程式隨堂測驗一

9

3

18

-3

(3,-2)

(-3,2)

(3,2)

(-3,-2)

$\left(x+4\right)^2+\left(y+3\right)^2=7$

$\left(x-4\right)^2+\left(y+3\right)^2=7$

$\left(x-4\right)^2+\left(y-3\right)^2=49$

$\left(x+4\right)^2+\left(y-3\right)^2=49$

$\left(x+3\right)^2+\left(y+1\right)^2=20$

$\left(x-1\right)^2+\left(y+3\right)^2=10$

$\left(x-3\right)^2+\left(y-1\right)^2=10$

$\left(x-1\right)^2+\left(y+3\right)^2=20$

(-3,-2)

(3,2)

(-6,-4)

(6,4)

1

2

3

4

 $\left(1,-3\right)$  

 $\left(\frac{1}{2},-\frac{3}{2}\right)$  

 $\left(-\frac{1}{2},\frac{3}{2}\right)$  

 $\left(-1,3\right)$  

 $\left(x+1\right)^2+\left(y-2\right)^2=3$  

 $\left(x-1\right)^2+\left(y+2\right)^2=3$  

 $\left(x-1\right)^2+\left(y+2\right)^2=9$  

 $\left(x+1\right)^2+\left(y-2\right)^2=9$  

3

2

 $2\sqrt{2}$  

 $3\sqrt{2}$  

 $\left(x-2\right)^2+\left(y-3\right)^2=4$  

 $\left(x-2\right)^2+\left(y-3\right)^2=16$  

 $\left(x+2\right)^2+\left(y+3\right)^2=3$  

 $\left(x+2\right)^2+\left(y+3\right)^2=16$