Trig Ratios & Finding Missing Sides

SOH CAH TOA

SAH COH TOA

SOH CAH TOH

SO CA TOA

$\sin\left(67\degree\right)=\frac{16}{x}$

$\sin\left(67\degree\right)=\frac{x}{16}$

$\tan\left(67\degree\right)=\frac{16}{x}$

$\cos\left(67\degree\right)=\frac{x}{16}$

$\cos\left(67\degree\right)=\frac{16}{x}$

$\cos\left(17\degree\right)=\frac{x}{14}$

$\cos\left(17\degree\right)=\frac{14}{x}$

$\sin\left(17\degree\right)=\frac{x}{14}$

$\sin\left(17\degree\right)=\frac{14}{x}$

$\tan\left(17\degree\right)=\frac{x}{14}$

$\tan\left(22\degree\right)=\frac{18}{x}$

$\tan\left(22\degree\right)=\frac{x}{18}$

$\sin\left(22\degree\right)=\frac{18}{x}$

$\sin\left(22\degree\right)=\frac{x}{18}$

$\cos\left(22\degree\right)=\frac{x}{18}$

$\tan\left(26\degree\right)=\frac{18}{x}$

$\tan\left(26\degree\right)=\frac{x}{18}$

$\sin\left(26\degree\right)=\frac{18}{x}$

$\sin\left(26\degree\right)=\frac{x}{18}$

$\cos\left(26\degree\right)=\frac{x}{18}$

$\sin\left(57\degree\right)=\frac{16}{x}$

$\sin\left(57\degree\right)=\frac{x}{16}$

$\cos\left(57\degree\right)=\frac{x}{16}$

$\tan\left(57\degree\right)=\frac{16}{x}$

$\cos\left(57\degree\right)=\frac{x}{16}$

$\cos\left(57\degree\right)=\frac{x}{11}$

$\cos\left(57\degree\right)=\frac{11}{x}$

$\tan\left(57\degree\right)=\frac{x}{11}$

$\tan\left(57\degree\right)=\frac{11}{x}$

$\sin\left(57\degree\right)=\frac{x}{11}$

 $\frac{8}{17}$  

 $\frac{15}{17}$  

 $\frac{17}{8}$  

 $\frac{8}{15}$  

Not possible

 $\frac{12}{13}$  

 $\frac{12}{5}$  

 $\frac{13}{12}$  

 $\frac{5}{13}$  

Not possible

 $\frac{13}{12}$  

 $\frac{13}{5}$  

 $\frac{12}{5}$  

 $\frac{5}{12}$  

Not possible