2 × 7 = \sqrt{2}\times\sqrt{7}= 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> × 7 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> =

14 \sqrt{14} 1 4 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

9 \sqrt{9} 9 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 + 7 = \sqrt{2}+\sqrt{7}= 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> + 7 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> =

9 \sqrt{9} 9 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

14 \sqrt{14} 1 4 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Μια εξίσωση πρώτου βαθμού

δεν μπορεί να έχει 2 λύσεις

έχει άπειρες λύσεις

Το Π.Θ. ισχύει

σε όλα τα ορθογώνια τρίγωνα

σε όλα τα τρίγωνα

σε μερικά ορθογώνια τρίγωνα

μόνο σε ισοσκελή τρίγωνα

Υποτείνουσα συναντάμε

σε ορθογώνια τρίγωνα

σε οξυγώνια τρίγωνα

σε αμβλυγώνια τρίγωνα

σε όλα τα τρίγωνα

Η τετραγωνική ρίζα ενός αρνητικού αριθμού

είναι αρνητικός αριθμός

είναι πάντα θετικός αριθμός

Με το Π.Θ. βρίσκουμε μια πλευρά ορθογωνίου τριγώνου όταν γνωρίζουμε

δυο οποιεσδήποτε πλευρές

Το αντίστροφο του Π.Θ. μας βοηθάει να:

διαπιστώσουμε αν ένα τρίγωνο είναι ορθογώνιο.

βρούμε το εμβαδόν του τριγώνου

υπολογίσουμε τις δύο κάθετες πλευρές.

υπολογίσουμε την υποτείνουσα.

Β'ΓΥΜΝΑΣΙΟΥ ΕΠΑΝΑΛΗΨΗ

Authored by Anastasia Kalogridou

Mathematics

7th - 9th Grade

Used 16+ times

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35 questions

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MULTIPLE CHOICE QUESTION

1 min • 1 pt

Η αδύνατη εξίσωση έχει

καμία λύση

μια λύση

άπειρες λύσεις

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Η αόριστη εξίσωση έχεις

άπειρες λύσεις

μια λύση

καμια λύση

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Η εξίσωση
$0χ=4$ είναι αόριστη

Σωστό

Λάθος

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Η εξίσωση
$0χ=0$ είναι αόριστη

Σωστό

Λάθος

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Ενα παραλληλόγραμμο έχει διαστάσεις 8 και 12 . Για να διπλασιάσουμε το εμβαδόν του ,αυξάνουμε τη μεγαλύτερη διάσταση κατα 4. Πόσο πρέπει να αυξήσουμε τη μικρότερη διάσταση;

192

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$\sqrt{2}\times\sqrt{7}=$

$\sqrt{14}$

$\sqrt{9}$

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$\sqrt{2}+\sqrt{7}=$

$\sqrt{9}$

$\sqrt{14}$

τίποτα απο τα προηγούμενα

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Το διπλάσιο του

$\sqrt{6}$ είναι $\sqrt{12}$

Σωστό

Λάθος

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Το διπλάσιο του $\sqrt{6}$ είναι $2\sqrt{6}$

Σωστό

Λάθος

10.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Το διπλάσιο του $\sqrt{7}$ είναι $\sqrt{28}$

Σωστό

Λάθος

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Β'ΓΥΜΝΑΣΙΟΥ ΕΠΑΝΑΛΗΨΗ

Η αδύνατη εξίσωση έχει

Η αόριστη εξίσωση έχεις

Η εξίσωση 0χ=40χ=40χ=4 είναι αόριστη

Η εξίσωση 0χ=00χ=00χ=0 είναι αόριστη

2×7=\sqrt{2}\times\sqrt{7}=2​×7​=

2+7=\sqrt{2}+\sqrt{7}=2​+7​=

Το διπλάσιο του 6\sqrt{6}6​ είναι 12\sqrt{12}12​

Το διπλάσιο του 6\sqrt{6}6​ είναι 262\sqrt{6}26​

Το διπλάσιο του 7\sqrt{7}7​ είναι 28\sqrt{28}28​

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Η εξίσωση
$0χ=4$ είναι αόριστη

Η εξίσωση
$0χ=0$ είναι αόριστη

$\sqrt{2}\times\sqrt{7}=$

$\sqrt{2}+\sqrt{7}=$

Το διπλάσιο του

$\sqrt{6}$ είναι $\sqrt{12}$

Το διπλάσιο του $\sqrt{6}$ είναι $2\sqrt{6}$

Το διπλάσιο του $\sqrt{7}$ είναι $\sqrt{28}$