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ULANGAN APLIKASI TURUNAN TRIGONOMETRI

Authored by Sri Rahayu

Mathematics

12th Grade

CCSS covered

Used 85+ times

ULANGAN APLIKASI TURUNAN TRIGONOMETRI
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10 questions

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1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Titik stasioner fungsi g(x)= -6 cos (3x +π ) untuk 0 < x ≤ π

{13π,23π, π}\left\{\frac{1}{3}\pi,\frac{2}{3}\pi,\ \pi\right\}

{0, 13π, 23π}\left\{0,\ \frac{1}{3}\pi,\ \frac{2}{3}\pi\right\}

{0, 13π. 23π, π}\left\{0,\ \frac{1}{3}\pi.\ \frac{2}{3}\pi,\ \pi\right\}

{0, 14π, 34π, π}\left\{0,\ \frac{1}{4}\pi,\ \frac{3}{4}\pi,\ \pi\right\}

{23π, π}\left\{\frac{2}{3}\pi,\ \pi\right\}

Tags

CCSS.HSF.TF.B.7

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

   Batas nilai x jika fungsi dibawah ini adalah fungsi naik

 f (x) = 2 sin⁡ (3x + 12π)f\ \left(x\right)\ =\ 2\ \sin\ \left(3x\ +\ \frac{1}{2}\pi\right)  dengan  0<x<π0<x<\pi  

 0<x<13π atau 13π <x<23π0<x<\frac{1}{3}\pi\ atau\ \frac{1}{3}\pi\ <x<\frac{2}{3}\pi  

 0<x<13π atau 23π<x<π0<x<\frac{1}{3}\pi\ atau\ \frac{2}{3}\pi<x<\pi  

 0<x<14π atau 12π<x<34π0<x<\frac{1}{4}\pi\ atau\ \frac{1}{2}\pi<x<\frac{3}{4}\pi  

 14π<x<12π\frac{1}{4}\pi<x<\frac{1}{2}\pi  

 13π<x<23π\frac{1}{3}\pi<x<\frac{2}{3}\pi  

Tags

CCSS.HSF.TF.A.4

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Nilai maksimum fungsi f(x) = 6 sin x + 8 cos x adalah....

-10

-8

-5

5

10

Tags

CCSS.HSF.TF.A.4

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 f (x) = 12−sin⁡ (x −π)f\ \left(x\right)\ =\ \frac{1}{2}-\sin\ \left(x\ -\pi\right)  

Titik balik minimum fungsi f untuk     0<x<2π0<x<2\pi  adalah....

 (12π, −12)\left(\frac{1}{2}\pi,\ -\frac{1}{2}\right)  

 (12π, 1)\left(\frac{1}{2}\pi,\ 1\right)  

 (32π,12)\left(\frac{3}{2}\pi,\frac{1}{2}\right)  

 (32π, −12)\left(\frac{3}{2}\pi,\ -\frac{1}{2}\right)  

 (32π, 1)\left(\frac{3}{2}\pi,\ 1\right)  

Tags

CCSS.HSF-IF.C.7E

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

 f (x) = 2 sin⁡ ( x − π4)f\ \left(x\right)\ =\ 2\ \sin\ \left(\ x\ -\ \frac{\pi}{4}\right)  

 Fungsi diatas  mempunyai daerah asal  0 ≤ x ≤ 2π,  fungsi tersebut cekung ke atas pada interval...

 0≤x<π4 atau 54π <x≤2π0\le x<\frac{\pi}{4}\ atau\ \frac{5}{4}\pi\ <x\le2\pi  

 0<x<π4atau 54π<x<2π0<x<\frac{\pi}{4}atau\ \frac{5}{4}\pi<x<2\pi  

 π4<x<54π\frac{\pi}{4}<x<\frac{5}{4}\pi  

 π4<x<34π\frac{\pi}{4}<x<\frac{3}{4}\pi  

 0<x<π4atau 34π<x<2π0<x<\frac{\pi}{4}atau\ \frac{3}{4}\pi<x<2\pi  

Tags

CCSS.HSF.TF.A.4

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 g (x) = cos⁡2 ( x−π3)g\ \left(x\right)\ =\ \cos^2\ \left(\ x-\frac{\pi}{3}\right)  

Grafik fungsi  melalui titik B yang berabsis π . Gradien garis singgung fungsi g di titik B adalah

 −233-\frac{2}{3}\sqrt{3}  

 −133-\frac{1}{3}\sqrt{3}  

 −122-\frac{1}{2}\sqrt{2}  

 122\frac{1}{2}\sqrt{2}  

 123\frac{1}{2}\sqrt{3}  

Tags

CCSS.HSF.TF.A.4

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Persamaan garis singgung grafik fungsi f(x) = 3 cos x + sin ( 2x- π ) di titik ( π , 3 ) adalah..

y= −2x −3+2πy=\ -2x\ -3+2\pi

y=−2x +3−2πy=-2x\ +3-2\pi

y= −2x+3+2πy=\ -2x+3+2\pi

y =−3x−2+3πy\ =-3x-2+3\pi

y =2x+3+2πy\ =2x+3+2\pi

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