Solve for h, S = 2 π r h 2\pi rh 2 π r h

h= S 2 π r \frac{S}{2\pi r} 2 π r S

h = S − 2 π r S-2\pi r S − 2 π r

h = 2 π r S \frac{2\pi r}{S} S 2 π r

A = b h 2 A=\frac{bh}{2} A = 2 b h Solve for b

b = 2 A h b=\frac{2A}{h} b = h 2 A

b = 2 A − h b=2A-h b = 2 A − h

b = A h 2 b=\frac{Ah}{2} b = 2 A h

b = A − 2 h b=\frac{A-2}{h} b = h A − 2

Solve for x y = mx + b

x = y − b m x=\frac{y-b}{m} x = m y − b

x = y b m x=\frac{yb}{m} x = m y b

x = y + b m x=\frac{y+b}{m} x = m y + b

p = 2 l + 2 w p\ =\ 2l\ +\ 2w p = 2 l + 2 w solve for w

w = p − 2 l 2 w=\frac{p-2l}{2} w = 2 p − 2 l

w = p 2 l − 2 w=\frac{p}{2l}-2 w = 2 l p − 2

w = p + 2 l 2 w=\frac{p+2l}{2} w = 2 p + 2 l

w = 2 p − l w=2p-l w = 2 p − l

V = 1 3 B h V=\frac{1}{3}Bh V = 3 1 B h Solve for h

h = 3 V B h=\frac{3V}{B} h = B 3 V

h = 1 3 V − B h=\frac{1}{3}V-B h = 3 1 V − B

h = 1 3 V B h=\frac{\frac{1}{3}V}{B} h = B 3 1 V

h = 3 V − B h=3V-B h = 3 V − B

F = 9 5 C + 32 F=\frac{9}{5}C+32 F = 5 9 C + 3 2 Solve for C

C = 5 9 ( F − 32 ) C=\frac{5}{9}\left(F-32\right) C = 9 5 ( F − 3 2 )

C = 9 5 ( F − 32 ) C=\frac{9}{5}\left(F-32\right) C = 5 9 ( F − 3 2 )

C = 9 5 F − 32 C=\frac{9}{5}F-32 C = 5 9 F − 3 2

C = 5 9 F − 32 C=\frac{5}{9}F\ -32 C = 9 5 F − 3 2

Solving Literal Equations

Authored by Katelyn Werner

Mathematics

8th - 9th Grade

CCSS covered

Used 8+ times

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25 questions

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MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Solve for x:

x = yb - v

x = by - v

x = by + v

Tags

CCSS.HSA.REI.B.3

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

S = 3F - 24 Solve for F

F = (S + 24)/3

F = S/3 + 24

F = 3S + 24

F = 3(S + 24)

Tags

CCSS.HSA.CED.A.4

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Solve the formula for r. What is the 1st step?

Divide each side by t.

Subtract t from each side.

Add t to each side.

Multiply each side by t.

Tags

CCSS.HSA.REI.A.1

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Solve for 'x': x + 2w = m

x = m - 2w

x = 0.5m - w

x = 2mw

x = m/(2w)

Tags

CCSS.HSA.REI.B.3

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Solve for w:
A = LW

A =^L/_W

w = ^L/_A

w = A

w = ^A/_L

Tags

CCSS.HSA.CED.A.4

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Solve:
C = 2πr, for r

C/(2π) = r

C + 2π = r

C - 2π = r

2πC = r

Tags

CCSS.HSA.CED.A.4

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Solve for x.
x + 7g = 9

x = 9 - 7g

x = 9 / 7g

x = 9 + 7g

x = 7g - 9

Tags

CCSS.7.EE.B.4A

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Solve for h, S = $2\pi rh$

h= $\frac{S}{2\pi r}$

h = $S2\pi r$

h = $S-2\pi r$

h = $\frac{2\pi r}{S}$

Tags

CCSS.HSA.CED.A.4

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$A=\frac{bh}{2}$

Solve for b

$b=2A-h$

$b=\frac{2A}{h}$

$b=\frac{Ah}{2}$

$b=\frac{A-2}{h}$

Tags

CCSS.HSA.CED.A.4

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Solving Literal Equations

Solve for x:

S = 3F - 24 Solve for F

Solve the formula for r. What is the 1st step?

Solve for 'x': x + 2w = m

Solve for w:A = LW

Solve:C = 2πr, for r

Solve for x. x + 7g = 9

Solve for h, S = 2πrh2\pi rh2πrh

A=bh2A=\frac{bh}{2}A=2bh​ Solve for b

Solve for by = mx + b

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Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Solve for w:
A = LW

Solve:
C = 2πr, for r

Solve for x.
x + 7g = 9

Solve for h, S = $2\pi rh$

$A=\frac{bh}{2}$

Solve for b

Solve for b
y = mx + b