Trig Test on Tan, Cot, Csc and Sec Graphs

y = secx

y = 2secx

y = 2cscx

y = cscx

y = -2cscx

down 11

reflection over the x - axis

phase shift = π/2 to the right

period = π

Amplitude is 6

down 4 units

phase shift = 2π/3 to the right

vertical stretch by a factor of 2

reflection over the x - axis

per = π/3

$\pi$

$2\pi$

$4\pi$

$\frac{3\pi}{2}$

$\frac{\pi}{2}$

$y=\csc\left(x+\frac{\pi}{2}\right)$

$y=\sec\left(x+\frac{\pi}{2}\right)$

$y=\csc\left(x-\frac{\pi}{2}\right)$

$y=\sec\left(x-\frac{\pi}{2}\right)$

$y\ =\ \csc\left(x-\frac{\pi}{4}\right)$

y = sec 2x

y = sec x

y = csc 2x

y = - sec x + 2

y = 2csc x

y=2csc(x)

y=csc(x) + 1

y=2csc(x) + 1

y= csc(x) + 2

$\frac{\pi}{4}$

$2\pi$

$\frac{\pi}{2}$

$\pi$

y=csc(x)

y=sec(x)

y=csc(x - π)

y= sec(x - π)

y=tan x

y=cot x

y= - tan 2x

y= - cot 2x + 2