КР Неравенства - май 2020, 7 клас

$\left(-\frac{1}{5}\right)^{3\ \ }<\left(-\frac{1}{3}\right)^3$

$\left(-1\right)^{3\ }>\left(-2\right)^3$

$\left(-\frac{1}{3}\right)^2>\left(\frac{1}{5}\right)^2$

$-\left(-5\right)^2<-\left|-5\right|$

$x<2x$

$x\ge2x$

$x<x-2$

$3-x<x$

$\left|x\right|<0$

$\left(x-1\right)^2\ge0$

$x+1<x$

$x-1>0$

$x\left(x-1\right)+1\le2x+x^2$

$x\left(x-1\right)-1\ge-2x+x^2$

$x\left(x-1\right)+1\ge-2x+x^2$

$x\left(x-1\right)-1\le2x+x^2$

 $\left(0;+\infty\right)$  

 $\left(-\infty;1\right)$  

 $\left(1;+\infty\right)$  

 $\left(-\infty;0\right]$  

AM > AB

AM < AB

AM ≥ AC

AM > AC

$AB=CD$

$AC=BD$

$AB<BD$

$CD>AC$