Manakah pernyataan berikut yang salah ....

cosec ⁡ α = m i r i n g d e p a n \operatorname{cosec}\alpha=\frac{miring}{depan} c o s e c α = d e p a n m i r i n g

cotan ⁡ α = s a m p i n g m i r i n g \operatorname{cotan}\alpha=\frac{samping}{miring} c o t a n α = m i r i n g s a m p i n g

cos ⁡ α = s a m p i n g m i r i n g \cos\alpha=\frac{samping}{miring} cos α = m i r i n g s a m p i n g

tan ⁡ α = d e p a n s a m p i n g \tan\alpha=\frac{depan}{samping} tan α = s a m p i n g d e p a n

sin ⁡ α = d e p a n m i r i n g \sin\alpha=\frac{depan}{miring} sin α = m i r i n g d e p a n

Dari gambar, pernyataan yang tidak benar adalah ....

cos ⁡ α = A C A B \cos\alpha=\frac{AC}{AB} cos α = A B A C

sin ⁡ α = B C A B \sin\alpha=\frac{BC}{AB} sin α = A B B C

sin ⁡ β = A C A B \sin\beta=\frac{AC}{AB} sin β = A B A C

cos ⁡ β = B C A C \cos\beta=\frac{BC}{AC} cos β = A C B C

tan ⁡ α = B C A C \tan\alpha=\frac{BC}{AC} tan α = A C B C

cos ⁡ α = . . . . \cos\alpha=\ \ \ .... cos α = . . . .

3 \sqrt{3} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 2 3 \frac{1}{2}\sqrt{3} 2 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 3 3 \frac{1}{3}\sqrt{3} 3 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

tan ⁡ P = 5 11 11 , maka nilai sin ⁡ P = \tan P=\frac{5\sqrt{11}}{11}\ ,\ \text{ maka}\ \text{ nilai}\ \ \sin P= tan P = 1 1 5 1 1 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> , maka nilai sin P =

5 11 \frac{5}{\sqrt{11}} 1 1 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 5

6 11 \frac{6}{\sqrt{11}} 1 1 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 6

11 5 \frac{\sqrt{11}}{5} 5 1 1 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

11 6 \frac{\sqrt{11}}{6} 6 1 1 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Dari gambar jika cos ⁡ θ = 2 3 , maka x = . . . . \text{Dari}\ \ \text{gambar}\ \ \text{jika}\ \ \cos\theta=\frac{2}{3},\ \text{maka}\ \ x=.... Dari gambar jika cos θ = 3 2 , maka x = . . . .

3 5 3\sqrt{5} 3 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

4 5 4\sqrt{5} 4 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

5 5 5\sqrt{5} 5 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

6 5 6\sqrt{5} 6 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

7 5 7\sqrt{5} 7 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Pernyataan berikut yang benar adalah...

Untuk a>0 a > 0 dan b>0 b > 0 maka grafik fungsi kuadrat akan terbuka ke atas dan bergeser ke kiri

Untuk a > 0 a>0 a > 0 dan b > 0 b>0 b > 0 maka grafik fungsi kuadrat akan terbuka ke atas dan bergeser ke kanan

Untuk a>0 a > 0 dan c > 0 c>0 c > 0 maka grafik fungsi kuadrat akan terbuka ke atas dan bergeser ke atas

Untuk a < 0 a<0 a < 0 dan c > 0 c>0 c > 0 maka grafik fungsi kuadrat akan terbuka ke atas dan bergeser ke atas

PAS MATEMATIKA SMK KELAS XI

Authored by anggri anti

Mathematics

11th Grade

CCSS covered

Used 107+ times

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40 questions

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MULTIPLE CHOICE QUESTION

3 mins • 12 pts

tan 30^o= ...

MULTIPLE CHOICE QUESTION

3 mins • 12 pts

Sin 0^o =

MULTIPLE CHOICE QUESTION

3 mins • 12 pts

tan 90^o= ...

MULTIPLE CHOICE QUESTION

3 mins • 12 pts

Cos 30^o = ...

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Diketahui ∆ ABC dengan ∠A = 60^o , sisi b = 12 cm dan sisi c = 8 cm. Tentukan panjang sisi a ....

2√7

√57

2√57

4√7

16√7

MULTIPLE CHOICE QUESTION

3 mins • 12 pts

Hitunglah luas ∆ ABC jika ∠C = 30^o , sisi a = 16 cm dan sisi b = 24 cm !

48 cm²

96 cm²

96√2 cm ²

192 cm²

192√2 cm²

Perbandingan antara sisi depan dan sisi miring pada segitiga siku-siku dalam trigonometri adalah….

sinus

cosinus

tangen

cosecan

secan

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Nilai Sin $\alpha\$ adalah....

$\frac{3}{5}$

$\frac{4}{5}$

$\frac{5}{4}$

$\frac{5}{3}$

$\frac{1}{5}$

10.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Nilai dari cos $\alpha$ pada segitiga ABC adalah....

$\frac{5}{13}$

$\frac{13}{5}$

$\frac{12}{13}$

$\frac{13}{15}$

$\frac{12}{5}$

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PAS MATEMATIKA SMK KELAS XI

tan 30o= ...

Sin 0o =

tan 90o= ...

Cos 30o = ...

Diketahui ∆ ABC dengan ∠A = 60o , sisi b = 12 cm dan sisi c = 8 cm. Tentukan panjang sisi a ....

Hitunglah luas ∆ ABC jika ∠C = 30o , sisi a = 16 cm dan sisi b = 24 cm !

Perbandingan antara sisi depan dan sisi miring pada segitiga siku-siku dalam trigonometri adalah….

Nilai Sin α \alpha\ α adalah....

Panjang AC pada segitiga ABC di atas adalah....

Nilai dari cos α\alphaα pada segitiga ABC adalah....

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Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

tan 30^o= ...

Sin 0^o =

tan 90^o= ...

Cos 30^o = ...

Diketahui ∆ ABC dengan ∠A = 60^o , sisi b = 12 cm dan sisi c = 8 cm. Tentukan panjang sisi a ....

Hitunglah luas ∆ ABC jika ∠C = 30^o , sisi a = 16 cm dan sisi b = 24 cm !

Nilai Sin $\alpha\$ adalah....

Nilai dari cos $\alpha$ pada segitiga ABC adalah....