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CALCULO II. FORMULAS 18 MARZO 2025

Authored by Jhonny Morales

Mathematics

1st Grade

Used 27+ times

CALCULO II. FORMULAS 18 MARZO 2025
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28 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

La integral indefinida de y=dxx2a2=y=\int_{ }\frac{dx}{\sqrt{x^2-a^2}}=  

 y=1aln(xx2a2)+cy=\frac{1}{a}\ln\left(x-\sqrt{x^2-a^2}\right)+c  

 y=ln(x+x2a2)+cy=-\ln\left(x+\sqrt{x^2-a^2}\right)+c  

 y=ln(x+x2a2)+cy=\ln\left(x+\sqrt{x^2-a^2}\right)+c  

Ninguno de los anteriores

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

La integral indefinida de y=a2x2 dx=y=\int_{ }\sqrt{a^2-x^2}\ dx= es:

Ninguno

 y=arcsen xa+cy=arcsen\ \frac{x}{a}+c  

y =  y=1aarcsen xa+cy=\frac{1}{a}arcsen\ \frac{x}{a}+c  

 y=x2a2x2+a22arcsen xa+cy=\frac{x}{2}\sqrt{a^2-x^2}+\frac{a^2}{2}arcsen\ \frac{x}{a}+c  

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

El resultado inmediato de la integral indefinida   y=dxa2+x2=y=\int_{ }\frac{dx}{\sqrt{a^2+x^2}}=     es:

 y=ln(x+a2+x2)+cy=\ln\left(x+\sqrt{a^2+x^2}\right)+c  

 y=12aln(x+x2±a2)+cy=\frac{1}{2a}\ln\left(x+\sqrt{x^2\pm a^2}\right)+c  

Ninguno

 y=ln(x+x2a2)+cy=\ln\left(x+\sqrt{x^2-a^2}\right)+c  

4.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

La integral indefinida inmediata de  y=dxa2x2y=\int_{ }\frac{dx}{\sqrt{a^2-x^2}}  

  y=arc cosxa+Cy=arc\ \cos\frac{x}{a}+C  

 y=12a arcsen xa+cy=\frac{1}{2a}\ arcsen\ \frac{x}{a}+c  

  y=arcsenxa +cy=arcsen\frac{x}{a}\ +c  

Ninguno

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

La integral indefinida inmediata de  y= dxa2x2y=\int_{ }\ \frac{dx}{a^2-x^2}   es

 y=arcsen xa+cy=arcsen\ \frac{x}{a}+c  

 y=12aln(axa+x)+cy=\frac{1}{2a}\ln\left(\frac{a-x}{a+x}\right)+c  

 y=12aln(a+xax)+cy=\frac{1}{2a}\ln\left(\frac{a+x}{a-x}\right)+c  

Ninguno

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

La integral indefinida inmediata de  y=dxx2a2y=\int_{ }\frac{dx}{x^2-a^2}    es:

Todos

 y=12a ln(xax+a)+cy=-\frac{1}{2a}\ \ln\left(\frac{x-a}{x+a}\right)+c  

 y=12aln(a+xax)+cy=\frac{1}{2a}\ln\left(\frac{a+x}{a-x}\right)+c 

 y=12aln (xax+a)+cy=\frac{1}{2a}\ln\ \left(\frac{x-a}{x+a}\right)+c 

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Resultado inmediato de la integral indefinida:  y=dxa2+x2y=\int_{ }\frac{dx}{a^2+x^2}  es:

 y=1a arctan xa+Cy=\frac{1}{a}\ \arctan\ \frac{x}{a}+C  

 y=1a arccot xa+Cy=-\frac{1}{a}\ \operatorname{arccot}\ \frac{x}{a}+C 

  y=1a arctan xa+Cy=-\frac{1}{a}\ \arctan\ \frac{x}{a}+C  

Ninguno

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