تحليل المعادلات التربيعية

$$\left(x-3\right)\left(x-5\right)=\ 0$$  

$$\left(x+3\right)\left(x+5\right)\ =0$$  

$$\left(x+3\right)\left(x-5\right)\ =\ 0$$  

$$\left(x-3\right)\left(x+5\right)\ =\ 0$$  

x = 3

x = -3

x = 3 ; x = -3

x = 0

$$\left(x-3\right)\left(x-5\right)=\ 0$$  

$$\left(x+3\right)\left(x+5\right)\ =0$$  

$$\left(x+3\right)\left(x-5\right)\ =\ 0$$  

$$\left(x-3\right)\left(x+5\right)\ =\ 0$$  

$$\left(x-3\right)\left(x-5\right)=\ 0$$  

$$\left(x+3\right)\left(x+5\right)\ =0$$  

$$\left(x+3\right)\left(x-5\right)\ =\ 0$$  

$$\left(x-3\right)\left(x+5\right)\ =\ 0$$  

$$\left(x-3\right)\left(x-5\right)=\ 0$$  

$$\left(x+3\right)\left(x+5\right)\ =0$$  

$$\left(x+3\right)\left(x-5\right)\ =\ 0$$  

$$\left(x-3\right)\left(x+5\right)\ =\ 0$$  

$$\left(x-3\right)\left(x-5\right)=\ 0$$  

$$\left(x+3\right)\left(x+5\right)\ =0$$  

$$\left(x+3\right)\left(x-5\right)\ =\ 0$$  

$$\left(x-3\right)\left(x+5\right)\ =\ 0$$