y = ∛(x-7)-2

y = ∛(x-2) -7

y = (x - 7)³ -2

y = (x-2)³ - 7

y = ∛(x-7)

y = ∛x -7

y = (x - 7)³

y = x³ - 7

f^-1(x)=4+∛(x+5)

f^-1(x)=∛(x+4) +5

f^-1(x)=5+(x+4)³

f^-1(x)=4+(x+5)³

f^-1(x)= ³√x+1

f^-1(x)= ³√x-1

f^-1(x)= (x-1)/3

f^-1(x)= (x+1)/3

f^-1(x)=∛(x-8) + 6

f^-1(x)=∛(x+6) - 8

f^-1(x)=(x+6)³ - 8

f^-1(x)=(x-8)³ + 6

f^-1(x)=4(x+3)³

f^-1(x)=(4x+12)³

f^-1(x)=3+1/4(x)³

f^-1(x)=1/4(x+3)³

$$f^{-1}\left(x\right)=\ \left(\frac{x-9}{3}\right)^3$$

$$f^{-1}\left(x\right)=\ \left(\frac{x-3}{9}\right)^3$$

$$f^{-1}\left(x\right)=^3\sqrt{\frac{x-9}{3}}$$

$$f^{-1}\left(x\right)=^3\sqrt{x-9}+3$$