(x + 3)² - 4

(x + 6)² - 4

(x + 3x)² - 4

(x + 3)² + 9

$$y=2\left(x-3\right)^2+9$$  

$$y=2\left(x+3\right)^2-6$$  

$$y=2\left(x+3\right)^2+12$$  

$$y=2\left(x+3\right)^2+21$$  

f(x) = 4(x + 4)² - 62

f(x) = 4(x - 4)² - 62

f(x) = 4(x - 8)² - 62

f(x) = 4(x + 8)² - 62

f(x) = 5(x+4)² - 3

f(x) = 4(x-4)² - 5

f(x) = 5(x+4)² +3

f(x) = 5(x-4)² + 157

$$f\left(x\right)=\left(x-4\right)^2+12$$  

$$f\left(x\right)=\left(x+4\right)^2$$  

$$f\left(x\right)=\left(x+4\right)^2-64$$  

$$f\left(x\right)=\left(x+4\right)-64$$  

y =(x+4)² - 64

y = (x + 4)² 64

y = (x +8)² + 16

y = (x -8)² + 16

y= 5(x-3)² +11

y = 5(x-3)² +605

y = 5(x-3)² +121

y= ( x -3)² + 5