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Ch. 8 Review

Ch. 8 Review

Assessment

Presentation

•

Mathematics

•

7th Grade

•

Practice Problem

•

Easy

•
CCSS
4.MD.A.3, 7.G.B.4, 6.G.A.1

+3

Standards-aligned

Created by

Victoria Lao

Used 5+ times

FREE Resource

43 Slides • 29 Questions

1

Perimeter

P = 15 + 13 + 9 + 9
= 46 ft

Add all the sides together

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2

Fill in the Blanks

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Find the perimeter.

P =

in.

3

Perimeter of a rectangle

P = 17 + 17 + 27 + 27
= 34 + 54
= 88 m

Add all the sides together

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4

Fill in the Blanks

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Find the perimeter of the rectangle.

P =

yd.

5

Fill in the Blanks

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Find the perimeter of the square.

P =

in.

6

Circumference

C = 2 ⋅ 3.14 ⋅ 6
= 37.68

C = 2⋅π⋅r

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7

Fill in the Blanks

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Find the circumference of the circle.

(Hint: C = 2⋅π⋅r)

C =

cm.

8

Circumference

C = 3.14 ⋅ 20
= 62.8 cm

C = π⋅d

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9

Fill in the Blanks

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Find the circumference of the circle.

(Hint: C = π⋅d)

C =

mm.

10

Finding Radius

C = 2⋅π⋅r
43.96 = 2 ⋅ 3.14 ⋅ r
43.96 = 6.28 ⋅ r




r = 7 ft

The circumference of a circular painting is 43.96 ft. What is the radius of the painting?

6.28

6.28

11

Fill in the Blanks

The circumference of a circular painting is 40.82 ft. What is the radius of the painting?

(Hint: C = 2⋅π⋅r)

r = _._ ft

12

Finding Diameter

C = π⋅d
59.66 = 3.14 ⋅ r
59.66 = 3.14 ⋅ r




d = 19 ft

The circumference of a circular painting is 59.66 ft. What is the radius of the painting?

3.14

3.14

13

Fill in the Blanks

The circumference of a circular field is 191.54 yd. What is the diameter of the field?

(Hint: C = π⋅d)

d =

yd

14

Finding the Area of a Circle

A = π⋅r2
= 3.14 ⋅ (4)2
= 3.14 ⋅ 16
= 50.24 cm2

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15

Fill in the Blanks

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Find the area of the circle.

(Hint: A = π⋅r2)

A = ___.__ cm2

16

Finding the Area of a Circle

A = π⋅r2
= 3.14 ⋅ (6)2
= 3.14 ⋅ 36
= 113.04 yd2

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17

Fill in the Blanks

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Find the area of the circle.

(Hint: A = π⋅r2)

A = ___.__ in2

18

Area of a Composite Shape

Area of rectangle
A = 23 ⋅ 14 = 322

Area of semicircle
A = π ⋅ r2 = 3.14 ⋅ (7)2 = 76.93
2 2

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​Total area = 322 + 76.93 = 398.93 ft2

19

Fill in the Blanks

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Find the area.

(Hint: Area of rectangle + Area of semicircle)

A = ___.__ ft2

20

Area of a Composite Shape

Area of rectangle
A = 93 ⋅ 66 = 6138

Area of 2 semicircles (1 circle)
A = π ⋅ r2 = 3.14 ⋅ (33)2 = 3419.46

​Total area = 6138 + 3419.46 = 9557.46 m2

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21

Fill in the Blanks

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Find the area.

(Hint: Area of rectangle + Area of 2 semicircles)

A = ____.__ m2

22

Area of a Composite Shape

Area of rectangle
A = 26 ⋅ 16 = 416

Area of semicircle
A = π ⋅ r2 = 3.14 ⋅ (8)2 = 100.48
2 2

​Total area = 416 - 100.48 = 315.52 in2

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23

Fill in the Blanks

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Find the area.

(Hint: Area of rectangle - Area of semicircle)

A = ___.__ ft2

24

Area of a Composite Shape

Area of rectangle
A = 37 ⋅ 16 = 592

Area of 2 semicircles (1 circle)
A = π ⋅ r2 = 3.14 ⋅ (8)2 = 200.96

​Total area = 592 - 200.96 = 391.04 cm2

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25

Fill in the Blanks

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Find the area.

(Hint: Area of rectangle - Area of 2 semicircles)

A = ___.__ cm2

26

Perimeter vs. Area

The distance around a shape

Ex: Nicole walking around the field.

The amount of space inside a shape

Ex: A field being covered by artificial turf

27

Multiple Choice

The court will have a wood floor.
Which measure would be used in finding the amount of wood needed?

1

Perimeter

2

Area

28

Multiple Choice

A strip of tape will be placed around the court.
Which measure would be used in finding the amount of tape needed?

1

Perimeter

2

Area

29

Multiple Choice

A silver wire will be placed around the window.
Which measure would be used in finding the amount of wire needed?

1

Perimeter

2

Area

30

Multiple Choice

The window's glass will be replaced.
Which measure would be used in finding the amount of glass needed?

1

Perimeter

2

Area

31

Word Problem

Rachel is staining the wooden floor of a court. The court is in the shape of a rectangle. It's length is 54 ft and it's width is 30 ft. Supposed each can of wood stain covers 135 sq ft. How many cans will she need to cover the court?

​

30

54

1620

1620 ÷ 135 = 12

12 cans

32

Fill in the Blanks

Lisa is fertilizing her garden. The garden is in the shape of a rectangle. Its length is 15 feet and its width is 12 feet. Suppose each bag of fertilizer covers 20 sq ft. How many bags will she need to cover the garden?

(Hint: Find the area of the rectangle and then divide)

_ bags

33

Word Problem

Chang wants to replace the wooden floor at his gym. The floor is in the shape of a rectangle. Its length is 35 feet and its width is 20 feet. Suppose wood flooring costs $13 for each sq ft. How much will the wood flooring cost for the floor?

​

20

35

700

700 ⋅ 13 = 9100

$9100

34

Fill in the Blanks

Jessica wants to wallpaper the back wall of her bedroom. The wall is in the shape of a rectangle. Its length is 13 feet and its width is 9 feet. Suppose wallpaper costs $7 for each sq ft. How much will wallpaper cost for the wall?

(Hint: Find the area of the rectangle and then multiply)

$

35

Word Problem

Tony wants to paint the ceiling of his restaurant. The ceiling is in the shape of a square. Its side lengths are 44 feet. Suppose each can of paint will cover 242 sq ft. How many cans will he need to paint the ceiling?

​

44

44

1936

1936 ÷ 242 = 7.99

8 cans

36

Fill in the Blanks

Keisha wants to paint the ceiling of her restaurant. The ceiling is in the shape of a square. Its side lengths are 48 feet. Suppose each can of paint will cover 192 square feet. How many cans will she need to paint the ceiling?

(Find the area of the square and then divide)

cans

37

Word Problem

Deon wants to replace a glass window in his restaurant. The window is in the shape of a square. Its side lengths are 8 feet. Suppose glass costs $6 for each sq ft. How much will the glass cost to replace the window?

​

8

8

64

64 ⋅ 6 = 384

$384

38

Fill in the Blanks

Kira wants to replace a glass window in her restaurant. The window is in the shape of a square. Its side lengths are 6 feet. Suppose glass costs $7 for each sq ft. How much will the glass cost to replace the window?

(Find the area of the square and then multiply)

$

39

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Area of a composite shape

40

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Area of a composite shape

41

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Area of a composite shape
​2 ft

42

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Area of a composite shape
​2 ft

14

43

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Area of a composite shape
​2 ft

14

21

44

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Area of a composite shape

A = 14 + 21

= 35 in2

​2 ft

14

21

45

Fill in the Blanks

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Find the area.

cm2

46

Area of a composite shape
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47

Area of a composite shape
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48

Area of a composite shape
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​8 ft

49

Area of a composite shape
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​8 ft

24

50

Area of a composite shape
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​8 ft

24

8

51

Area of a composite shape

A = 24 + 8

= 32 ft2

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​8 ft

24

8

52

Fill in the Blanks

media image

Find the area.

in2

53

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Area of a composite shape

54

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Area of a composite shape

55

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Area of a composite shape

21

21

56

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Area of a composite shape

A = 21 + 6 + 21

= 48 ft2

​2 ft

21

6

​2 ft

21

57

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Area of a composite shape
​2 ft

21

6

​2 ft

21

58

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Area of a composite shape

A = 21 + 6 + 21

= 48 ft2

​2 ft

21

6

​2 ft

21

59

Fill in the Blanks

media image

Find the area.

cm2

60

Area of a Triangle

A = b⋅h = 9 ⋅ 12 = 54 cm2
2 2

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61

Fill in the Blanks

media image

Find the area.

ft2

62

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Area of a Triangle

A = b⋅h = 11 ⋅ 8 = 44 cm2
2 2

63

Fill in the Blanks

media image

Find the area.

yd2

64

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Area of a Triangle

A = b⋅h = 23 ⋅ 7 = 80.5 cm2
2 2

65

Fill in the Blanks

media image

Find the area.

ft2

66

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Area of a Ring

7

67

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Area of a Ring

10

7

68

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Area of a Ring

Outer Ring
A = π⋅r2 = 3.14 ⋅ (10)2 = 314



10

7

69

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Area of a Ring

Outer Ring
A = π⋅r2 = 3.14 ⋅ (10)2 = 314

Inner Ring
A = π⋅r2 = 3.14 ⋅ (7)2 = 153.86


10

7

70

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Area of a Ring

Outer Ring
A = π⋅r2 = 3.14 ⋅ (10)2 = 314

Inner Ring
A = π⋅r2 = 3.14 ⋅ (7)2 = 153.86


Total: A = 314 - 153.86 = 160.14

10

7

71

Fill in the Blanks

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Find the area.

yd2

72

Fill in the Blanks

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Find the area.

in2

pattern-tertiary
Perimeter

P = 15 + 13 + 9 + 9
= 46 ft

Add all the sides together

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