Bài học không có tiêu đề

BO GIAO DVC VA DAO TAO �CONG HOA XX MI ait NGIIIA VIVT NAM
DO 14p - Tw do - 1-13nh phtic

se): �

/BGDDT-GDTrH �

Ha N0i, ngay �thang nam 2024
V/v thuc hirt Ici6'm tra, danh gia d6i v6ri
cap THCS, THPT

Kinh �

Cac Gido due va Dao tap

De thuc hien viec kiem tra, danh gia theo quy dinh tai Thong to s6
22/2021/TT-BGDDT ngdy 20/7/2021 quy dinh ye danh gia hoc sinh trung hoc co'
ser va hoc sinh trung hoc pho th6ng cua B6 truerng B6 Gido due va Da° tao

,
(GDDT), B6 GDDT nghi cac Sd GDDT can cir not dung da duoc tap huan cho
gido vien cot can vao thang 11/20241, to chirc tap huan cho can b6 quail ii, gido
vien cua cac co se( giao chic có thuc hien chuung trinh gido due pho thong tren dia
ban quan
D6i \Teri cac mon hoc danh gia bang nhan xet ket hop danh gia bang diem s6,
So GDDT huong dan cac co so' gido chic er cap trung hoc pith thong xay dung ma
tran, ban dac td, de kiem tra va huang dan cham de kiem tra dinh ki bao dam cac
yeu cau ve chuyen men, ki thuat (tham khdo Phu luc kern theo); trong nam hoc
2024-2025 trien khai thuc hien Ur hoc ki 2.
Trong qua trinh dux hien, neu c6 vuong mac, de nghi So GDDT phan anh
ye B6 GDDT (qua IN Gido due Trung hoc).

Nei nliem:
- Nhu tren;
- BO truCrng (a bao cao); „
- Tr. PhamNgoc Thuong (de bao cao);
- Vu truCtng (de bao cao);
- Ltru: VT, Via GDTrH.

TL. BO TRU.CiNG
KT. IT TRU'ONG VLJ GIRO TRUNG HOC
PHO VU TRUI3NG

Do Dtrc Que

I COng van s6 6569/BGDDT-GDTrH ngay 16/10/2024 v6 viec tap huan gido vien cot can v6 tang cueing nang Urc
thuc h*.1 CT GDPT 2018 citaB0 GDDT.

7991

17

12

(Kern theo Gong van so

0
o

.-

1,3 >

CV)

U

....I �

..C3

"0 �0

..

:5
,cd �

>

,..) �

.—
— �

<0

crl. �L. �0

0

�

zzi �•<o
7., �C,] �..,7,
X �7
Z ▪ C

<co. ... �`Z
... Q
•C'd �4.

C4) ...i'

'CO �,'-'2 0 Ct. . �.,
0 .5

�

0 �,...F,
0 0
..4 �0 clC)
7 �0 .0 cn
co3 �„,t •<0 tO .. coa
'01. �4C1 :5 -o
-o �••<2 -c 1
to <0. <g ..

o �.0 u —

o

i:J.

..=o �0 0 ..0 0.

,..) �..<0.) :5 OA
• -, �›, ..0 0
.7 7 7 .7 <77 tx)

O. 0 U

"C ...

..c 0• �

.• �.-5, <0 Fr

A nu. E
:]: m
'>- �g..,o *7
..... 4 ,„5, 0,

?‹,
E �0.0 o
O 07. 7 7
7 0
7 1) § •>N
7- 1:17 ,c1 0
7 `,..,^ b. <0 -
-CO
�cy
0 *7
10/J �.•<0 0 V v) ,4

O p:o 2 1-' 0
..sz z �`g 0
,•o lz <0 pp va
• Z g • ,., ts ..• �7 7 - �3.
. ...., , �.
...
,<0 •,..,0 ‘0 �.
.4 ..z �C-) 1.-)
.-1 $10., ,4- ,e,

2..1' �5
p; ,: ;t

to
= ...co
E•

: �",....
4

cn rn

=
4

cr.) ("")

A-1
..c2

c> p

Mfrc do danh gia

=
get.
=
b.

= " =
,.0
s
cf., C)
=
•<1,)

... sl
'ac,

TNKQ �

Trci loi ngan9

= ta ,

2,0

c>
N
= ,..„>
E
..•
...,,,,
• P.1
f:0

C' •ttt
qk1
Cop
I
t)41
' h
.1
,-

= r4"
03. "
›.. �=1

C) N C::, CI

,cy=
=
WI

•d- S

Ka)-i-)
....1
=

Nhieu hfa chon

" =

rn 6
rn
KC1.)
E

A.+ ‘<z)

g P

7+5
=

Z.

= k<CL)

.7
4

TOng so cau
TOng so diem

eic"'

eg

at
g
= A
C.) �c.,)
...
ti=1

Chu de 1

Chu c16' 2

E*

1-1

N

S6 can hoi a cac ink do danh gia

0
<0.
0
b•

tt,
<0. = 4

Cr:),, rn c)
cr)
0
WI)

i...
':.?..
0:1

TNKQ
Trci lai ngan

0 g
›- 4

N
C)
CI

.I.) ..<0.) ..,..4
=

Z.:
.F5

040z

gIll

V
(03*
›. * mjcs

CI

C=>,,

20

1
"..--., C`•
0

4.4 ,.<14 I:Q

chop

qA 0

c)
en o
cr)
0

..-.
Pel

Yeu clau can dat

•

. •

r=
1
• •
.

.
•

�

..> �:

�

1 �•

. .
-ij

�

CO �:

�

1 �•

•

''
.
:
•

.
•
>
.
:
•

Noi
duns/dun vi
lien fink

Ttong se; du

C <4;:.

le

la

60 I

10

1...4
KCI)

C..)

eA
...01)

C..)

Fl

--I

N

0

bA

O

<0

-o

bD

bA
O

U

fro

CIA
fro

cc!

<2

• ro

00

)0.

<0

Z.

0

•co