Alg2 Fall Semester Final Review/Practice

x = -4

$$a=4;\ h=-2;\ k=3$$  

$$a=2;\ h=4;\ k=-3$$  

$$a=4;\ h=2;\ k=3$$  

$$a=3;\ h=2;\ k=-4$$  

$$f\left(x\right)=4\left(x+2\right)^2+3$$  

$$f\left(x\right)=4\left(x-2\right)^2+3$$  

$$f\left(x\right)=3\left(x+2\right)^2+4$$  

$$f\left(x\right)=2\left(x-4\right)^2+3$$  

By graphing the equation.

By using the quadratic formula.

By completing the square.

By factoring the equation.

None of these make sense to do

(x + 3)(x + 10)

(x - 3)(x - 10)

(x + 3)(x - 10)

(x - 3)(x + 10)

$$\pm6$$  

$$-6$$  

$$6i$$  

$$\pm6i$$  

$$10+10i$$  

$$1-5i$$  

$$6-4i^2$$  

$$10$$  

$$10+10i$$  

$$1-5i$$  

$$6-4i^2$$  

$$10$$  

6i√5

-8√5

8i√5

-8i√5

Re=3.5

Im=2.7

Re=3.5

Im=-2.7

Re=-3.5

Im=2.7

Re=-3.5

Im=-2.7

Yes, because $$f\left(1\right)=0.$$  

Yes, because $$f\left(-1\right)=0.$$  

No, because $$f\left(1\right)=0.$$  

No, because $$f\left(-1\right)=0.$$