

等差數列求和
Presentation
•
Mathematics
•
10th Grade
•
Medium
math eozgy
Used 3+ times
FREE Resource
6 Slides • 3 Questions
1
2
Match
等差數列公式配對
通項公式
求和公式1
求和公式2
等差中項
an=a1+(n−1)d
Sn=2(a1+an)×n
Sn=na1+2n(n−1)×d
A=2a+b
3
Multiple Choice
計算1+3+5+7+……+19的和,則下列哪一個列式是正確的?
2(1+19)×19
2(1+19)×10
9×1+29×8×2
19×1+219×18×2
4
Draw
求數列所有項的和:
5
例4. 考慮等差數列-25, -21, -17, …, 求該數列由第21項至第30項之和
6
例. 求1至300間能被6整除之一切整數之和。
7
例. 求1至500間能被6或9整除之一切整數之和。
8
9
已知等差数列的前n项和为𝑺n,若𝒂1=𝟏𝟎,公差d=-2,则𝑺n是否存在最大值?若存在,求𝑺𝒏的最大值及取得最大值是n的值;若不存在,说明理由.
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