Electric Motor

Presentation

•

Physics

•

12th Grade

•

Practice Problem

•

Easy

Risdiyanto Risdi

Used 3+ times

FREE Resource

7 Slides • 10 Questions

Open Ended

Tulis Nama Lengkap dan Kelas

Type response here

Open Ended

Discuss with your partner!
What do the tools in the picture have in common?
(apa kesamaan alat-alat dalam gambar)

Type response here

The tools mentioned earlier all have electric motors. An electric motor helps convert electrical energy into mechanical energy. It is based on the principles of electromagnetism.

What is electric motor?

Construction of an electric motor

Match

Match the following

Komponen X dan Y

Komponen P dan Q

Sumber medan magnet

Sumber arus listrik

Kumparan berputar

Sikat penghubung arus & cincin berputar

Cincin berputar

It has a rectangular coil of wire ABCD.
It has got a strong horseshoe magnet. The coil ABCD is placed perpendicular to this magnet.
The ends of the coil ABCD are connected to split rings P and Q. These split rings play the role of the commutator. It helps reverse the direction of the current flow.

The inners part of the split rings is insulated. It is attached to the axle. The axle is free to rotate.
The external side of the conducting edges of the split rings is connected with the stationary brushes. These brushes X and Y are connected with the battery. This completes the circuit.

Replace this

Open Ended

Tuliskan secara singkat dan jelas hal-hal yang dipahami dari slide sebelum ini!

Type response here

Multiple Choice

Ke mana arah gaya magnet pada kawat AB?

atas

bawah

kanan

kiri

Multiple Choice

Ke mana arah gaya magnet pada kawat CD?

atas

bawah

kanan

kiri

Open Ended

Tuliskan secara singkat dan jelas hal-hal yang dipahami dari slide sebelum ini!

Type response here

Bagaimana menghitung momen gaya pada kumparan?

Multiple Choice

Rumus dasar menghitung momen gaya (M) adalah ...

M = Fr

M = F r cos q

M = F r sin q

M = F r / sinq

M = F r / cosq

Rumus momen gaya pada kumparan?

Multiple Choice

Momen gaya pada kumparan dengan N lilitan, luas A, dialiri arus i, dan terletak dalam medan magnet B yang membentuk sudut q terhadap normal bidang kumparan adalah ...

M = NABi cosq

M = NABi sinq

M = NABi tanq

M = NABi / cosq

M = NABi / sinq

Multiple Choice

4,8 x 10^-3

9,6 x 10^-3

4,8 x 10^-5

9,6 x 10^-5

9,6 x 10^-6

Keep working hard and stay humble!

Congratulations for finishing the lesson!

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