Unit 1B quiz #3 review

(- infinity, infinity)

[2, infinity)

(-infinity, -2]

(-2, infinity)

$$f^{-1}\left(x\right)=\ \left(\frac{x-9}{3}\right)^3$$

$$f^{-1}\left(x\right)=\ \left(\frac{x-3}{9}\right)^3$$

$$f^{-1}\left(x\right)=^3\sqrt{\frac{x-9}{3}}$$

$$f^{-1}\left(x\right)=^3\sqrt{x-9}+3$$

$$f^{-1}\left(x\right)=^3\sqrt{5x+5}-4$$

$$f^{-1}\left(x\right)=^3\sqrt{5x+1}$$

$$f^{-1}\left(x\right)=^3\sqrt{5x+9}$$

$$f^{-1}\left(x\right)=^3\sqrt{5x-4}+5$$

(-2,-2)

(-2,2)

(2,-2)

(2,2)

x + 5

x – 5

x + 1

x + 2

(2x – 3)(x + 2)

2x² + x - 6

(2x + 3)(x - 2)

(5n²+3)(n-2)

(5n³+3)(n-2)

(5n²-3)(n-2)

10n(n²-6)

3 roots

4 roots

5 roots

6 roots

x-intercept

zero

root

all of these.

1

2

3

4

$$f\left(x\right)=x^4\left(x-5\right)^2\left(x-3\right)$$

$$f\left(x\right)=x^4\left(x+5\right)^2\left(x+3\right)$$

$$f\left(x\right)=x\left(x-5\right)^4\left(x-3\right)^2$$

$$f\left(x\right)=x\left(x+5\right)^2\left(x+3\right)^4$$