
Limiting Reactants
Presentation
•
Chemistry
•
10th Grade
•
Practice Problem
•
Medium
+1
Standards-aligned
Matthew McCombs
Used 5+ times
FREE Resource
17 Slides • 6 Questions
1
Let's start on Page 5 of the packet.
Question 1 asks you to write a balanced chemical equation.
Limiting Reactants
2
Categorize
H2(g)
O2(g)
H2O(g)
The reaction between hydrogen gas and oxygen gas creates water vapor. Organize the substances involved in the reaction.
3
Hydrogen and Oxygen are both diatomic.
Often times, Hydrogen is drawn an empty circle but Oxygen tends to be a red circle.
O
H
H
O
4
Particle Diagram
A molecule of water tends to be drawn with two circles and one red circle.
O
H
H
5
Multiple Choice
Is this the balanced chemical equation for hydrogen gas reacting with oxygen gas to produce water vapor:
2H2(g)+O2(g)→ 2H2O(g)
Yes
No
6
Multiple Choice
Is this an accurate particle diagram of the reaction?
Yes
No
7
Dropdown
8
According to the problem, before they began there were 4 molecules of both hydrogen gas and oxygen gas.
9
Before: | 4 | | 4 | | 0 |
|---|---|---|---|---|---|
Change: | | | | | |
After: | | | | | |
10
Particle Diagram:
According to the diagram, 4 water molecules were made, all of the hydrogen gas was consumed, and there were 2 molecules of oxygen leftover.
11
Before: | 4 | | 4 | | 0 |
|---|---|---|---|---|---|
Change: | -4 | | -2 | | +4 |
After: | 0 | | 2 | | 4 |
12
You will need a piece of paper to take notes.
Watch the clip.
Let's step it up a notch.
13
Multiple Choice
What is the first step in using a BCA table?
Make sure the chemical equation is balanced.
Identify the given information.
Determine what is needed to be found
Find the mole ratios.
14
20.0g of CaCl2
20.0g of AgNO3
Balanced equation allow us to use mole ratios, but before that, all mass needs to be converted into moles.
15
Categorize
.118 mol
.180 mol
How many moles did you get?
16
The ratio of AgNO3 to CaCl2 is 2:1. Therefore, if .180 moles of CaCl2 is used, that would mean 2x more AgNO3 is needed (.360 moles). Is there enough?
17
18
The ratio of AgNO3 to CaCl2 is 2:1. Therefore, if .118 moles of AgNO3 is used, that would mean 1/2x CaCl2 is needed (.059 moles). Is there enough?
19
20
The ratio of AgNO3 to AgCl is 1:1. Therefore, if .118 moles of AgNO3 is used, that would mean the same amount of AgCl is made.
21
The ratio of AgNO3 to Ca(NO3)2 is 2:1. Therefore, if .118 moles of AgNO3 is used, that would mean 1/2x Ca(NO3)2 is made (.059 moles).
22
B: .118 .180 0 0
C: -.118 -.059 +.059 +.180
A: 0 .121 .059 .180
Now convert the moles into grams using the molar mass. You can google them. :)
23
Problem #2, Page 6
Let's start on Page 5 of the packet.
Question 1 asks you to write a balanced chemical equation.
Limiting Reactants
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