Lesson 28.1

$$2.5$$

$$5$$

$$5\sqrt{3}$$

$$10$$

6

8

10

not possible to determine

6

8

10

good question

$$\frac{Opposite\ Leg}{Adjacent\ Leg}$$

$$\frac{Opposite\ Leg}{Hypotenuse}$$

$$\frac{Adjacent\ Leg}{Hypotenuse}$$

$$\frac{Hypotenuse}{Adjacent\ Leg}$$

$$\frac{Opposite\ Leg}{Adjacent\ Leg}$$

$$\frac{Opposite\ Leg}{Hypotenuse}$$

$$\frac{Adjacent\ Leg}{Hypotenuse}$$

$$\frac{Hypotenuse}{Adjacent\ Leg}$$

$$\frac{Opposite\ Leg}{Adjacent\ Leg}$$

$$\frac{Opposite\ Leg}{Hypotenuse}$$

$$\frac{Adjacent\ Leg}{Hypotenuse}$$

$$\frac{Hypotenuse}{Adjacent\ Leg}$$

$$\sin40=\frac{x}{19}$$

$$\cos40=\frac{x}{19}$$

$$\tan40=\frac{x}{19}$$

x =sin^–1(25/24)

x = sin^–1(24/25)

x = sin^–1(25/7)

x = sin^–1(7/25)

$$x=\sin^{-1}\left(\frac{56}{70}\right)$$

$$x=\sin^{-1}\left(\frac{70}{56}\right)$$

$$x=\sin^{-1}\left(\frac{70}{42}\right)$$

$$x=\sin^{-1}\left(\frac{42}{70}\right)$$

$$\sin\left(\theta\right)=\frac{20}{25}$$  

$$\cos\left(\theta\right)=\frac{20}{25}$$  

$$\tan\left(\theta\right)=\frac{20}{25}$$  

$$\sin\left(\theta\right)=\frac{25}{20}$$