Inverse of linear function.

$$f^{-1}\left(x\right)=\frac{x+5}{8}$$

$$y=\frac{x+5}{8}$$

$$f^{-1}\left(x\right)=\frac{x+8}{5}$$

$$f^{-1}\left(x\right)=5x+8$$

$$y=\frac{1}{6}x-7$$

$$f^{-1}\left(x\right)=\frac{1}{6}x-7$$

$$f^{-1}\left(x\right)=\frac{1}{42}x-6$$

$$f\left(x\right)=\frac{1}{6}x-7$$

All of the above.

$$f^{-1}\left(x\right)=\frac{4}{3}\left(x-9\right)$$

$$f^{-1}\left(x\right)=\frac{4}{3}x-12$$

$$y=\frac{3}{4}x-12$$

$$f\left(x\right)=\frac{5}{2}x-40$$

$$f^{-1}\left(x\right)=\frac{5}{2}x+40$$

$$f\left(x\right)=\frac{5}{2}x+40$$

$$f^{-1}\left(x\right)=\frac{5}{2}x-40$$

$$f^{-1}\left(x\right)=\frac{4x-5}{3}$$

$$f\left(x\right)^{-1}=\frac{5x}{3}$$

$$f\left(x\right)=5x-3$$

$$f^{-1}\left(x\right)=\frac{4x-3}{4}$$

$$y=-\frac{5}{4}x+\frac{1}{4}$$

$$f^{-1}\left(x\right)=-\frac{5}{4}x+\frac{1}{4}$$

$$f^{-1}\left(x\right)=\frac{4x-5}{7}$$

$$f^{-1}\left(x\right)=\frac{-4x-6}{5}$$