(P3T7Q2) Area between curves [CLASS//QUIZIZZ]

$$\left(8x+6\right)-\left(x-x^2\right)$$

STEP 2:

Simplify the expresion inside the integral before integrate.

$$\int_{ }\left(x^2+7x+6\right)dx$$

STEP 3:

Calculate the antiderivative.

(do not right down the +C)

$$\left[\frac{x^3}{3}+7\frac{x^2}{2}+6x\right]_{-6}^{-1}$$

STEP 4:

Evaluate in the upper limit.

(write down 3 decimals without rounding)

$$\left[\frac{x^3}{3}+7\frac{x^2}{2}+6x\right]_{-6}^{-1}$$

STEP 5:

Evaluate in the lower limit.

(write down 3 decimals without rounding)

$$\left[\frac{x^3}{3}+7\frac{x^2}{2}+6x\right]_{-6}^{-1}$$

STEP 6:

Subtract the lower evaluation from the upper evaluation.

(write down 3 decimals without rounding)

STEP 7:

FINAL ANSWER

So the area of the region

between the graphs is...

(write down 3 decimals without rounding)

$$\int_{-6}^{-2}\left(\frac{4}{x}\right)-\left(5\right)dx$$ =___?

(do not round up intermediate computations, write down the answer with 3 decimals without rounding)

$$\left(x^2+2x\right)-\left(2x+1\right)$$

STEP 4:

Simplify the expresion inside the integral before integrate.

$$\int_{ }\left(x^2-1\right)dx$$

STEP 5:

Calculate the antiderivative.

(do not right down the +C)

$$\left[\frac{x^3}{3}-x\right]_{-1}^1$$

STEP 6:

Evaluate in the upper limit.

(write down 3 decimals without rounding)

$$\left[\frac{x^3}{3}-x\right]_{-1}^1$$

STEP 7:

Evaluate in the lower limit.

(write down 3 decimals without rounding)

$$\left[\frac{x^3}{3}+7\frac{x^2}{2}+6x\right]_{-6}^{-1}$$

STEP 8:

FINAL ANSWER

Subtract the lower evaluation from the upper evaluation.

(write down 3 decimals without rounding)

Remember what happens if you get a negative number!!

$$\int_?^?\left(\sqrt[]{x+7}\right)-\left(0.5\left(x+7\right)\right)dx$$ =___?

(do not round up intermediate computations, write down the answer with 3 decimals without rounding)