Rational Expressions

(x+1)(x-1)

(x+1)² (x-1)

(2x+2)

We set the numerator equal to zero and solve for the variable

We set the denominator equal to zero and solve for the variable

We plug zero into the numerator and simplify

We plug zero into the denominator and simplify

$$x\ne\pm16$$  

$$x\ne-4$$  

$$x\ne\pm4$$  

$$x\ne4$$  

$$\frac{5x-9}{\left(x-5\right)\left(x+4\right)\left(x+3\right)}\ ,\ x\ne-5,\ 3,\ 4$$  

$$\frac{5x-11}{\left(x-5\right)\left(x+4\right)\left(x+3\right)}\ ,\ x\ne-4,\ -3,\ 5$$  

$$\frac{5x-11}{\left(x-5\right)\left(x+4\right)\left(x+3\right)}\ ,\ x\ne-5,\ 3,\ 4$$  

$$\frac{5x-9}{\left(x-5\right)\left(x+4\right)\left(x+3\right)}\ ,\ x\ne-4,\ -3,\ 5$$  

$$\frac{x^2-24}{\left(x+6\right)\left(x-6\right)}\ ,\ x\ne\pm6$$  

$$\frac{x^3+6x^2-24x}{\left(x^2-36\right)\left(x+6\right)}\ x\ne-6,\ 36$$  

$$\frac{x^2+2x-24}{\left(x+6\right)\left(x-6\right)}\ ,\ x\ne\pm6$$  

$$\frac{x^2+12x+24}{\left(x+6\right)\left(x-6\right)}\ ,\ x\ne\pm6$$  

$$\frac{x^2-2x-8}{2x+7}\ ,\ x\ne-\frac{7}{2}$$

$$x^2-2x-8\ ,\ x\ne0$$  

$$x^2-2x+2\ ,\ x\ne0$$  

$$\frac{x^2-2x+2}{2x+7}\ ,\ \ x\ne-\frac{7}{2}$$  

$$\frac{-2x^2-11x-3}{\left(2x-3\right)\left(2x+3\right)}\ ,\ x\ne\pm\frac{2}{3}$$  

$$\frac{-2x^2-11x-3}{\left(2x-3\right)\left(2x+3\right)}\ ,\ x\ne\pm\frac{3}{2}$$  

$$\frac{-2x^2+5x+3}{\left(2x-3\right)\left(2x+3\right)}\ ,\ x\ne\pm\frac{3}{2}$$  

$$\frac{-2x^2+5x+3}{\left(2x-3\right)\left(2x+3\right)}\ ,\ x\ne\pm\frac{2}{3}$$  

$$\frac{-x^2+3x-34}{\left(x+8\right)\left(x-4\right)}\ ,\ x\ne-8,\ 4$$  

$$\frac{-x^2+3x-34}{\left(x+8\right)\left(x-4\right)}\ ,\ x\ne-4,\ 8$$  

$$\frac{-x^2-3x+46}{\left(x+8\right)\left(x-4\right)}\ ,\ x\ne-8,\ 4$$  

$$\frac{-x^2-3x+46}{\left(x+8\right)\left(x-4\right)}\ ,\ x\ne-4,\ 8$$  

$$\frac{6x}{ay}$$  

$$\frac{6}{a}$$  

$$\frac{9x}{y}$$  

$$\frac{6x}{9y}$$  

$$\frac{7(r+2)}{r+2}$$

$$\frac{r-8}{r+2}$$

$$\frac{r+2}{7}$$

$$\frac{r-8}{7}$$

A

B

C

D

$$\frac{4(x+3)}{x+2}$$

$$\frac{x+2}{4(x+1)}$$

$$\frac{x+2}{4(x+3)}$$

$$\frac{4(x+1)}{x+2}$$

$$\frac{4}{7}\div\frac{1}{7}$$  

$$\frac{4}{7}\times\frac{1}{7}$$  

$$\frac{4}{7}\times\frac{7}{1}$$  

$$\frac{7}{4}\times\frac{7}{1}$$  

$$y^2$$  

$$\frac{1}{x}$$  

$$\frac{x^2}{2y}$$  

$$\frac{y^2}{x}$$  

A

B

C

D