Review Section 1.7

3 x y³

8 x³ y

3 x³ y

8 x y³

x - 3

-21

-3

( x - 3 ) / ( x )

( x + 5 )( x - 5 ) / ( x + 5 )( x - 2 )

( x - 5 ) / ( x - 2 )

( x + 5 ) / ( x - 2 )

-25 / ( 3x - 10 )

4(x+3)/(x+2),

(x+2)/4(x+1)

(x+2)/4(x+3),

4(x+1)/(x+2),

$$\frac{1}{b\left(b-2\right)};\ b\ne0,\ 2$$  

$$\frac{b-3}{3b^2\left(b+6\right)};\ b\ne-6,\ 0$$  

$$b-8;\ b\ =\ all\ real\ numbers$$  

$$\frac{3b\left(b-7\right)}{b+3};\ b\ \ne-3,\ 1,\ 2$$  

$$7;\ x\ =\ all\ real\ numbers$$  

$$\frac{x+5}{3x};\ x\ne0$$  

$$21x;\ x\ =\ all\ real\ numbers$$  

$$-\frac{8}{7x};\ x\ne-3,\ 0,\ 8$$  

1/6

x+10/ 6x+60

x+8/ 6x+60 

(x+10)(x+8)/ 6x+60

A

B

C

D

$$\frac{4k^2}{k-7}$$  

$$\frac{9}{k+7}$$  

$$\frac{9}{4}$$  

1

A.

B.

C.

D.

$$\frac{2x-4}{x+2}$$  

$$\frac{8x-4}{x+2}$$  

$$\frac{2x-2}{x+2}$$  

$$\frac{2x-2}{0}$$  

$$\frac{8}{\left(x-2\right)\left(x+7\right)}$$  

$$\frac{8}{2x+5}$$  

$$\frac{8x}{\left(x-2\right)\left(x+7\right)}$$  

$$\frac{8x+29}{\left(x-2\right)\left(x+7\right)}$$  

$$\frac{4c^6}{a^2}$$  

$$\frac{1a^2c^6}{4}$$  

$$\frac{1c^6}{4a^2}$$  

$$\frac{1a^2}{4c^6}$$  

$$\frac{1}{5y}$$  

$$-5y$$  

$$-5x^{10}y^{17}$$  

$$\frac{-5}{y}$$  

$$\frac{x}{x+3}$$  

$$\frac{x}{x-3}$$  

$$\frac{x+6}{x-3}$$  

$$\frac{x}{x+6}$$  

$$\frac{x-5}{x+2}$$  

$$\frac{x-5}{x-2}$$  

$$\frac{x+5}{x+2}$$  

$$\frac{x+5}{x-2}$$  

$$\frac{x+5}{x-1}$$  

$$\frac{x-5}{x-1}$$  

$$\frac{x+5}{x+1}$$  

$$\frac{x-5}{x+1}$$  

10 / 14a⁴

21 / 49a⁴

3 / a⁴

3 / 7a⁴

$$\frac{4\left(x-4\right)}{\left(x+5\right)}$$

$$\frac{\left(x+4\right)^2\left(x-4\right)}{16\left(x+5\right)}$$

Can't be simplified

$$\frac{\left(x+5\right)}{4\left(x-4\right)\ }$$

$$\frac{2a\left(a+7\right)}{a+3}$$  

$$\frac{5a}{a-6}$$  

$$a-7$$  

$$\frac{a+7}{a+3}$$  

$$\frac{1}{b\left(b-2\right)};\ b\ne0,\ 2$$  

$$\frac{b-3}{3b^2\left(b+6\right)};\ b\ne-6,\ 0$$  

$$b-8;\ b\ =\ all\ real\ numbers$$  

$$\frac{3b\left(b-7\right)}{b+3};\ b\ \ne-3,\ 1,\ 2$$  

$$7;\ x\ =\ all\ real\ numbers$$  

$$\frac{x+5}{3x};\ x\ne0$$  

$$21x;\ x\ =\ all\ real\ numbers$$  

$$-\frac{8}{7x};\ x\ne-3,\ 0,\ 8$$  

$$\frac{n+6}{16n^4};\ n\ne0$$  

$$\frac{6n}{\left(n-4\right)\left(n+6\right)};\ n\ne-6,\ 4$$  

$$\frac{3\left(n-8\right)}{n+8};\ n\ne-8$$  

$$\frac{n+8}{5};\ n\ne4,\ 5,\ 6$$  

$$\frac{6\left(a+2\right)}{a+4}$$  

$$\frac{6}{a+4}$$  

$$\frac{6a+12}{\left(a+2\right)\left(a+4\right)}$$  

$$\frac{6\left(a+2\right)}{\left(a+2\right)\left(a+4\right)}$$  

A

B

C

D