Review: Adding Fractions

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Practice Problem

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Wendi Hensley

Used 11+ times

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16 Slides • 12 Questions

Adding Fractions with Unlike Denominators

Uncommon Denominator

A fraction that has the bottom number that is not the same. Or when two fractions have different denominators.

How can we find a common denominator?

The denominator need to be the same for both fractions

We need to multiply both denominator and numerator by the same number.

Equivalent Fractions

Common Denominator

Multiple Choice

What is an equivalent fraction to $\frac{1}{2}$ ?

$\frac{2}{3}$

$\frac{4}{6}$

$\frac{5}{10}$

$\frac{3}{8}$

Multiple Choice

What is an equivalent fraction to $\frac{2}{3}$ ?

$\frac{3}{6}$

$\frac{6}{9}$

$\frac{8}{15}$

$\frac{4}{9}$

Multiple Choice

What is an equivalent fraction to $\frac{3}{4}$ ?

$\frac{6}{12}$

$\frac{12}{20}$

$\frac{6}{8}$

$\frac{9}{15}$

Multiple Choice

What is an equivalent fraction to $\frac{2}{5}$ ?

$\frac{10}{25}$

$\frac{12}{20}$

$\frac{6}{10}$ 12

$\frac{10}{30}$

Common Denominator:

Both numerator and denominator need to be the same in order for us to add them.

Problem #1

1

5

2

4 +

=

Fill in the Blanks

Type answer...

Problem #1

1

5

2

4 +

=

20 Problem #1

1

5

2

4 +

=

20

Multiple Choice

What I do to the numerator I also.....

need to do to the terminator

need to add

need to do to the denominator

Problem #1

1

5

2

4 +

=

20

4

10

Multiple Choice

$\frac{1}{5}$ + $\frac{2}{4}$ =

$\frac{14}{20}$

$\frac{3}{20}$

$\frac{10}{4}$

$\frac{3}{9}$

Problem #2

2

5

1

10 +

=

50 Problem #2

2

5

1

10 +

50 =

50

10x

Multiple Choice

$\frac{2}{5}$ is equivalent to $\frac{ }{50}$ ?

$\frac{3}{50}$

$\frac{15}{50}$

$\frac{20}{50}$

Problem #2

2

5

1

10 +

50 =

50

10x

20

10x

Multiple Choice

$\frac{1}{10}$ is equivalent to $\frac{ }{50}$ ?

$\frac{3}{50}$

$\frac{5}{50}$

$\frac{10}{50}$

Problem #

1

5

2

4 +

=

20

4

10 Problem #2

2

5

1

10 +

50 =

50

10x

20

10x

5 Problem #2

2

5

1

10 +

=

50

Poll

$\frac{2}{5}$ + $\frac{1}{10}$ =

$\frac{3}{50}$

$\frac{5}{20}$

$\frac{7}{11}$

$\frac{25}{50}$

Let's Practice adding fractions with unlike denominators

Multiple Choice

$\frac{5}{6}$ + $\frac{5}{11}$ =

$\frac{85}{66}$

$\frac{66}{55}$

$\frac{11}{66}$

$\frac{10}{17}$

Multiple Choice

$\frac{2}{5}$ + $\frac{1}{8}$ =

$\frac{3}{40}$

$\frac{21}{40}$

$\frac{6}{16}$

Adding Fractions with Unlike Denominators

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Review: Adding Fractions

Uncommon Denominator

Common Denominator

Common Denominator:

Problem #1

​1

5

​2

4

+

=

Problem #1

​1

5

​2

4

+

=

20

20

Problem #1

​1

5

​2

4

+

=

20

20

Problem #1

​1

5

​2

4

+

=

20

20

4

10

Problem #2

​2

5

​1

10

+

=

50

Problem #2

​2

5

​1

10

+

50

=

50

50

Problem #2

​2

5

​1

10

+

50

=

50

50

20

Problem #

​1

5

​2

4

+

=

20

20

4

10

1

2

1

2

1

2

1

2

2

1

2

1

2

1

1

2

2

1

2

1