

BPGHS SJChO Chemical Equilibrium I
Presentation
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Chemistry
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9th - 12th Grade
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Practice Problem
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Hard
Wong Leng
FREE Resource
44 Slides • 26 Questions
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Multiple Choice
1. (Lv.1) Which of the following is the correct Kc expression for the reversible reaction 2HBr(g) --> H2(g) + Br2(g)?
{[H2(g)][HBr(g)]}/
{[Br2(g)]2}
{2[HBr(g)]}/
{[H2(g)]2[Br2(g)]}
{[H2(g)][Br2(g)]}/
{[HBr(g)]2}
{[Br2(g)][H2(g)]}/
{2[HBr(g)]}
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Multiple Choice
2. (Lv.1) For the Kc expression derived from question 1, what are the correct Kc units?
Dimensionless
mol-1dm3
moldm-3
mol2dm-6
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Multiple Choice
3. (Lv.2) When aqueous ammonia, NH3(aq) is added to Zinc Hydroxide, Zn(OH2) in large excess, a miraculous phenomenon occurs where the precipitate dissolves! The reversible equilibrium is given by: Zn(OH)2(s) + 4NH3(aq) --> Zn(NH3)42+(aq) + 2OH-(aq). What is the correct Kc expression for the above dissolution reaction?
{[NH3(aq)]4[OH-(aq)]2}/
{[Zn(NH3)42+(aq)]2[Zn(OH)2(s)]}
{4[NH3(aq)]}/{[Zn(NH3)42+(aq)][OH-(aq)]2}
{[Zn(NH3)42+(aq)][OH-(aq)]2}/
{[NH3(aq)]4}
{[Zn(OH)2(s)][Zn(NH3)42+(aq)]}/{[NH3(aq)]4[OH-(aq)]2}
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Multiple Choice
4. (Lv. 1) For the Kc expression derived from question 3, what are the correct Kc units?
Dimensionless
mol2dm-6
moldm-3
mol-1dm3
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Multiple Choice
5. (Lv. 2) A metal displacement reaction occurs when a more reactive metal is exposed to a "salt solution" of the less reactive metal. For a solution of Iron(III) Nitrate, Zinc metal was added, prompting such a reaction to take place. By means of writing the ionic equation for this displacement reaction, derive the Kc expression for this particular metal displacement reaction.
{[Fe(s)]2}/
{[Zn2+(aq)]3}
{[Zn2+(aq)]3}/
{[Fe3+(aq)]2}
{2[Fe(s)]}/
{[Zn(s)]3}
{[Zn2+(aq)]3[Fe(s)]2}/
{[Fe3+(aq)]2[Zn(s)]3}
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Answer/Feedback:
Ionic equation: 3Zn(s) + 2Fe3+(aq) --> 3Zn2+(aq) + 2Fe(s).
Solids are not included into the Kc expression.
Do make it a point to write your state symbols so that you know clearly what to include and what to exclude from Kc!
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Multiple Choice
6. (Lv. 1) For the Kc expression derived from question 5, what are the correct Kc units?
Dimensionless
moldm-3
mol2dm-6
mol3dm-9
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Multiple Choice
7. (Lv. 1) In an experiment to study the formation of Hydrogen Iodide, I2(g) + H2(g) --> 2HI(g), the equilibrium concentrations of I2(g), H2(g) and HI(g) were 1.06x10-3moldm-3, 6.50x10-5moldm-3 and 1.80x10-3moldm-3 respectively. Calculate the Kc of this equilibrium reaction, assuming no temperature changes.
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0.212
26125
6.856
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Answer/Feedback:
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Multiple Choice
8. (Lv. 2) At a certain temperature, the value of Kc for the equilibrium system HCN(aq) + H2O(l) --> CN-(aq) + H3O+(aq) is 6.20x10-10moldm-3. What is the new Kc value for the following reaction: 2HCN(aq) + 2H2O(l) --> 2CN-(aq) + 2H3O+(aq)?
1.24x10-9moldm-3
3.84x10-19mol2dm-6
2.49x10-5mol2dm-6
1.24x10-9
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Answer/Feedback:
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Multiple Choice
9. (Lv. 2) 2 equilibria are as shown below:
Equilibria I: 2X2(g) + Y2(g) --> 2X2Y
Equilibria II: X2Y --> X2(g) + 1/2Y2(g)
If the value of Kc for the 1st equilibria is 2M, under the same conditions of temperature, what is the value of Kc for equilibria II?
0.707M-1/2
0.500M-1
-0.250M
1M2
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Answer/Feedback:
Since the reaction is reversed, by writing the reverse Kc expression, you can see that it is an inverse of the original Kc. Moreover, the moles of each of the chemical entities are divided by 1/2 - these will be raised to the powers. This means that a square root is needed too. The final answer should be 1/sqrt(2).
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Multiple Choice
10. (Lv. 2) At a certain temperature, the dissolution of 1 mole of AgCl(s) in an aqueous medium has a Kc value of 1.60x10-10mol2dm-6. What is the value of Kc for the precipitation of 4 moles of AgCl(s) from its constituent (aq) ions?
2.81x102mol2dm-6
6.4x10-10moldm-3
6.55x10-32mol4dm-12
1.53x1039mol-8dm24
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Answer/Feedback:
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Multiple Choice
11. (Lv. 2) A chemist employed by the National Environment Agency (NEA) is tasked to study catalytic converters in relation to urban smog. The chemist is tasked to find Kc for the following equilibrium reaction: 2NO2(g) --> 2O2(g) + N2(g)
Given the following data:
2NO2(g) --> 2NO(g) + O2(g) Kc=1.10x10-5moldm-3
0.5O2(g) + 0.5N2(g) --> NO(g) Kc=4.80x10-10
Calculate unknown Kc for the reaction that the chemist is tasked to study.
1.59x10-12mol-1dm3
2.29x104moldm-3
4.77x1013moldm-3
0.000011mol-1dm3
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Answer/Feedback:
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Multiple Choice
12. (Lv. 2) The depletion of ozone in the upper atmosphere is a very pressing environmental issue. The overall equation is O3(g) --> O(g) + O2(g).
Given the following data:
NO2(g) --> NO(g) + O(g) Kc=7.80x10-45moldm-3
NO2(g) + O2(g) --> NO(g) + O3(g) Kc=1.70x1033
Calculate the unknown Kc for the depletion of ozone.
4.59x10-78moldm-3
2.29x10-52moldm-3
1.326x10-11moldm-3
3.83x10-36moldm-3
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Answer/Feedback:
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Multiple Choice
13. (Lv. 3) At temperature TK, 3 equilibrium constants for their respective equilibrium systems are as shown below:
CO2(g) + H2(g) --> CO(g) + H2O(g) K1=0.2
C(s) + CO2(g) --> 2CO(g) K2= 6.2moldm-3
C(s) + 1/2O2(g) --> CO(g) K3=3.30x104(moldm-3)0.5
Using the above, what is the value of Kc for the following equilibrium: 3CO2(g) + H2(g) --> 3CO(g) + H2O(g) + O2(g) at temperature TK?
1.67x10-7mol-1dm3
2.70x10-8
7.06x10-9moldm-3
4.09x10-4mol2dm-6
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Answer/Feedback:
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Multiple Choice
14. (Lv. 1) Calcium Carbonate, CaCO3 readily decomposes upon heating to give solid calcium oxide and gaseous carbon dioxide. Which of the following is the correct expression for Kp?
PCO2(g)
{PCO2(g)PCaO(s)}/
PCaCO3(s)
1/{PCO2(g)2}
It is not possible to have an expression for Kp in this scenario.
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Multiple Choice
15. (Lv. 1) For the Kp expression derived from question 13, what are the correct Kp units?
atm
atm-1
atm2
atm-2
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Multiple Choice
16. (Lv. 1) For the following reversible reaction: 4NH3(g) + 7O2(g) --> 4NO2(g) + 6H2O(l), what is the correct Kp expression?
{PNO2(g)46PH2O(l)}/{PO2(g)7}
{PNO2(g)4}/
{PNH3(g)4PO2(g)7}
{PNH3(g)4PO2(g)7}/
{PNO2(g)4PH2O(l)6}
{PNH3(g)4PNO2(g)4}/{PO2(g)7}
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Multiple Choice
17. (Lv. 1) For the Kp expression derived from question 14, what are the correct Kp units?
Pa4
Pa-3
Pa-7
Pa
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Multiple Choice
18. (Lv. 2) Calculate Kp for the reaction 2IF3(s) + 3Ne(g) --> 3NeF2(s) + I2(s), given that the equilibrium amounts of Ne, NeF2 and I2 are all the same, while Ne exerts a pressure of 2.90kPa at equilibrium.
2900Pa
4.10x10-2Pa
2.44x1010Pa-1
4.10x10-11Pa-3
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Answer/Feedback:
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Multiple Choice
19. (Lv. 2) At 1000oC, the following reaction C(s) + 2H2(g) --> CH4(g) has Kp of 0.262atm-1. At equilibrium, the partial pressure of Methane is 12.2kPa. What is the equilibrium partial pressure of Hydrogen?
21.40kPa
0.459atm
6.82kPa
0.678atm
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Answer/Feedback:
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Multiple Choice
20. (Lv. 2) At a certain temperature, the value of Kp for the reversible equilibrium reaction 3O2(g) --> 2O3(g) is 8.00atm-1. What is the value of Kp for the following reaction: 2O3(g) --> 3O2(g)?
0.583
2.828atm2
2.000atm-1
0.125atm
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Answer/Feedback:
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Multiple Choice
21. (Lv. 2) A gaseous equilibrium mixture in a flask at temperature T was found to consist of 0.50mol of SO2(g), 0.12mol of O2(g) and 5.0mol of SO3(g). The total pressure inside the flask was 800kPa.
5.85kPa-1
0.584kPa-1
8.15kPa-1
6.44kPa-1
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Answer/Feedback:
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Multiple Choice
22. (Lv. 1) The water-gas shift reaction plays a central role in the chemical methods for obtaining cleaner fuels from coal. The reaction is given by: CO(g) + H2O(g) --> H2(g) + CO2(g). At a temperature of TK, the Kp is 2.7. Calculate the value of Kc for the same reaction.
1.643
2.700
4.436
3.554
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Answer/Feedback:
Kp=Kc(RT)2-2, so (RT)0 = 1, thus, Kp = Kc.
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Multiple Choice
23. (Lv. 1) 2.00moles each of SO2(g), SO3(g) and O2(g) are mixed and allowed to react in a 2l container. If the Kc of the reaction: 2SO2(g) + O2(g) --> 2SO3(g) is 0.8moldm-3, what will happen to the chemical system in this current state?
The backward rate will be favoured.
The forward rate will be favoured.
There will be no net changes in the current position of equilibrium.
Impossible to predict as there is not enough data.
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Answer/Feedback:
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Multiple Choice
24. (Lv. 1) At 425oC, for the following reaction 2HBr(g) --> H2(g) + Br2(g), Kp=4.18x10-9. In 1 experiment, 1.00atm of HBr(g), 0.010atm of H2(g) and 0.010atm of Br2(g) were introduced into a reaction vessel. What will happen to this chemical system?
Position of equilibrium will shift to the reactants.
Position of Equilibrium will shift to the products.
The system is at equilibrium, so there will be no net changes that take place.
All 3 aforementioned options will occur.
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Answer/Feedback:
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Multiple Choice
25. (Lv. 1) At room temperature, the equilibrium constant, Kc for the following reaction 2NO(g) --> O2(g) + N2(g) is 1.4x1030. 560g of N2(g) was mixed with 320g of O2(g) and 90g of NO(g). What will happen to this chemical system?
Position of equilibrium shifts to the right.
Position of equilibrium shifts to the left.
The chemical system is in equilibrium, so no net changes will occur.
Impossible to tell, as the total volume of the chemical system is not given - i.e., concentration of each of the chemicals are unknown.
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Answer/Feedback:
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