
Vector
Presentation
•
Mathematics
•
University
•
Easy
Ong jun
Used 1+ times
FREE Resource
9 Slides • 14 Questions
1
Most of the vectors are used to find the coordinates of apoint position.Not only that,we can also use vectors to find the speed at which something is moving or increasing.
Group 2
What is Vector
2
Change The Point To The Vector
Question:-
a. A(3,3), B(-2, 2) b. A (8, 0, -2), B(5, 3, 1)
c. A(-1,8), B(5, 9) d. A (0, 7, 5), B(11, 5, 0)
3
Multiple Choice
Find the XY
If the X(12, -13 , -4) and Y(20 , -6 , 0)
(6 , 7, 4)
(8 , 7, 4)
(8 , -19, -4)
(-6 , -7, -4)
4
Multiple Choice
Change the point to be vector , GP .
If the points is G(3, 0) and P(2, 7)
(-1 , 7)
(1 , -7)
( 1 , -7)
5
Magnitude or length
The length of 2-dimensional vector a =
The length of 3-dimensional vector a =
Find the Magnitude
1.A(1 , 2 , 3) and B(3 , 3 , 4)
2.X(1 , 3 ) and Y(1 , 4 )
is
is
6
Multiple Choice
Find the ∣a∣ ,When A⟨2,3⟩ and B ⟨-2,1⟩
-4.4721
4.4721
Cannot be calculated
4.4722
7
Multiple Choice
Find the magnitude for the vector a=⟨6,0,3⟩
5
1
3.2361
-3.2361
8
Vector Addition
If a=
and b=
,then
and
A)Given that a=6i -j +3k ,b=5j + k
1.a+b
2.a-b
1. (6i - j + 3k) + (0i + 5j + k)
=(6+0)i +(-1+5)j +(3+1)k
=6i + 4j + 4k
2.(6i - j + 3k) - (0i + 5j + k)
=(6-0)i +(-1-5)j +(3-1)k
=6i + (-6)j + 2k
=6i - 6j + 2k
B)Given that a=⟨-4 ,3) ,(6, 2)
3a
2.-4a + 5b
1.3a=(-4(3) , 3(3) )
=(-12 , 9)
2.-4a + 5b =(-4(-4) ,3(-4)) + (6(5) , 2(5))
=(16 , -12) + (30 , 10)
=(46, -2)
9
Multiple Choice
If a=⟨6,0,3⟩ ,b=⟨-1,5,-2⟩.
Find the 21a+2b
(1 , 10 , −25 )
(10, 10 , 25 )
(1, 10 , 25 )
(10 ,10 , −25 )
10
Multiple Choice
If a=i + 6j - k, b=7i - k
Find the -4a + 5b
31i -24j -k
31i + 24j -k
-31i -24j +k
31i - 24j +k
11
Multiple Choice
If a=2i - j + 2k , b=4j+2k
Find the ∣a∣ and ∣b∣
∣a∣ = 3
∣b∣ = 20
∣a∣ = 29
∣b∣ = 20
∣a∣ =3
∣b∣ = 29
∣a∣ =3
∣b∣ =2
12
Algebraic Properties of Vectors
Commutative (vector) P + Q = Q + P
Associative (vector) (P + Q) + R = P + (Q + R)
Additive identity There is a vector 0 such that (P + 0) = P = (0 + P) for all P
Additive inverse For any P there is a vector -P such that P + (-P) = 0
Distributive (vector) r(P + Q) = rP + rQ
Distributive (scalar) (r + s) P = rP + sP
Associative (scalar) r(sP) = (rs)P
Multiplicative identity For the real number 1, 1P = P for each P
Additional For Basic Knowlegde
Unit vector
A vector of length 1 is called a unit vector.
In an xy -coordinate system the unit vector is denoted by i and j
In an xyz -coordinate system the unit vector is denoted by i, j and k
13
Dot Product
If a=
and b=
then their dot product is:
This also applies to 3-space vectors
Find the Dot product
1.a=⟨4, -1⟩ ,b=⟨3, 6⟩
2. a=i -2j +3k ,b=5i + 9k
=4(3) + 6(-1)
=6
Properties of the Dot Product
(Commutative Property) For any two vectors A and B, A.B = B.A.
(Scalar Multiplication Property) For any two vectors A and B and any real number c, (cA).B = A.(cB) = c(A.B)
(Distributive Property) For any 3 vectors A, B and C, A.(B+C) = A.B + A.C.
Additional information
=5(1) + 0(-2) + 9(3)
=5+0+27
=32
1.
2.
14
Multiple Choice
Find the Dot Product.
If a=⟨5 ,0, 2⟩ , b=⟨3, -1 , 10⟩
-5
5
35
-35
15
Multiple Choice
Find the Dot Product.
If a=2i + 9j ,b=4i - 3k
8
-8
4
-4
16
Angle Between The Vectors
The angle between two vectors a and b is found using the formula
Find the angle between the vectors
1.a=3i + 4j – k and b=2i – j + k.
First Step :Find the Dot Product
= (3i + 4j – k).(2i – j + k)
= (3)(2) + (4)(-1) + (-1)(1)
= 6-4-1
= 1
Last Step:put all the values you just found into the Formula
17
Multiple Choice
Find the between angle the vectors.
If a=(1 , 2 ,3) and b(4 ,0 ,-1).Giving your answer in 4 decimal places and radian
1.5059rad
-1.5059rad
1.6067rad
-1.6067rad
18
Multiple Choice
Find the angle between the vectors.
If a=j + k , b= i + 2j - 3k. Giving your answer in 4 decimal places and radian
1.7609rad
-1.7609rad
100.89rad
-100.89rad
19
Cross Product
this are for three-dimensional vectors only.
if the a=
and b=
then the cross product is
20
Question of Cross Product
1.Find the cross product for a=⟨1,2,3⟩ b=⟨1,2,3⟩
2.Find the cross product for a=2i + j - k ,b=j + 2k
i j k
2 1 -1
0 1 2
=(2-(-1))i - (4-0)j + (2-0)k
=3i -4j + 2k
=⟨3 ,-4 , 2⟩
21
Multiple Choice
Find the Cross product A×B
if a=2i + 6j -4k , b=-3i -9j + 6k
⟨0 , 0 ,0⟩
⟨72 ,-24 ,0⟩
-24j+36k
72i -24j - 36k
22
Multiple Choice
Find the Cross product A×B
If a=⟨1 , 2 ,0⟩ , b=⟨0 , 3 ,1⟩
⟨1 , 1 ,3⟩
2i -j +3k
⟨0 , -1 ,3⟩
i + j- 3k
23
Multiple Choice
Find the A×B
If ∣a∣ =12 , ∣b∣ =15 and the angle between a and b is 6π
155.88°
155.89°
168.34°
122.78°
Most of the vectors are used to find the coordinates of apoint position.Not only that,we can also use vectors to find the speed at which something is moving or increasing.
Group 2
What is Vector
Show answer
Auto Play
Slide 1 / 23
SLIDE
Similar Resources on Wayground
16 questions
Tema 7: integración por sustitución
Presentation
•
University
16 questions
Statistik 1 - Ukuran Pemusatan
Presentation
•
University
19 questions
Common Errors- Subject and Verb Agreement-2
Presentation
•
University
20 questions
UNIT 9. COMPARATIVES AND SUPERLATIVES.
Presentation
•
University
17 questions
Statistics
Presentation
•
University
15 questions
Solving Multi-Step Equations
Presentation
•
University
17 questions
Peluang Kejadian Majemuk
Presentation
•
12th Grade
19 questions
Plano Cartesiano!!
Presentation
•
12th Grade
Popular Resources on Wayground
24 questions
PBIS-HGMS Day 10
Quiz
•
6th - 8th Grade
10 questions
HCS SCI 03 Summer School Review 3
Quiz
•
3rd Grade
11 questions
Home Scope
Quiz
•
7th - 8th Grade
15 questions
HCS SCI 05 Summer School Assessment 3 Review
Quiz
•
5th Grade
35 questions
Lufkin Road Middle School Student Handbook & Policies Assessment
Quiz
•
7th Grade
18 questions
Geo 11.3 Area of Circles and Sectors
Quiz
•
9th - 11th Grade