10

3

4

-3

A positive coefficient for $$x^2$$ & the equation set equal to 0.

Factor and cancel

Distribute and combine like terms

There is no such thing as a quadratic equation

Factor

Subtract 6 from both sides to set the equation equal to 0

Set each factor equal to 0

Combine like terms

$$x=-5$$  

$$x=5$$  

$$x=0$$  

$$x=3\ \ \ \&\ \ \ x=10$$  

$$x=-3\ \ \ \&\ \ \ x=-10$$  

$$x=-2\ \ \ \&\ \ \ x=15$$

$$x=2\ \ \ \&\ \ \ x=-15$$  

a = 4, b = -8, c = 3

a = 4, b =-8, c =-3

a = 4, b = 8, c = 3

a = 4, b = 8, c = -3

x = -2, 3

x = 2, 3

x = 2, -3

x = -2, -3

$$x=\frac{7}{2},\ x=-6$$  

$$x=-\frac{5}{2},\ x=5$$  

$$x=-\frac{3}{7},\ x=6$$  

$$x=-\frac{5}{2},\ x=7$$  

$$x=-1.5,\ 5$$  

No Solution

$$x=-5,\ 1.5$$  

$$x=0.7,\ 5$$  

1. Move the constant to the right side.

2. Factor the perfect square trinomial

3. Add $$\left(\frac{b}{2}\right)^2$$   on both sides of the equation.

4. Write two equations and solve

1. Add $$\left(\frac{b}{2}\right)^2$$   on both sides of the equation.

2. Move the constant to the right side

3. Factor the perfect square trinomial

4. Write two equations and solve

1. Move the constant to the right side

2. Add $$\left(\frac{b}{2}\right)^2$$   on both sides of the equation.

3. Factor the perfect square trinomial

4. Write two equations and solve

1. Add $$\left(\frac{b}{2}\right)^2$$   on both sides of the equation.

2. Move the constant to the right side

3. Write two equations and solve

4. Factor the perfect square trinomial.

$$x^2-10=11$$  

$$x^2-10x+11=-11$$  

$$x^2+10x-11=11$$  

$$x^2-10x=-11$$  

   1

  11

  -11

-1 

aX² + bX + c

b - 4ac

b² - 4ac

b² + 4ac

2 real solutions

2 imaginary solution

1 solution

3 solutions

76

-7

9

none of these