
Advanced Algebra, 10.1 Operations and COmposition
Presentation
•
Mathematics
•
10th - 12th Grade
•
Hard
+1
Standards-aligned
Jeremy Adelmann
Used 18+ times
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7 Slides • 10 Questions
1
Advanced Algebra,
10.1 Operations and Composition
By Jeremy Adelmann
2
Multiple Choice
Simplify.
(x2+1)+(3x+5)
x2+3x+6
x2−3x−4
3x3+5x2+3x+5
3x+5x2+1
x−35+9x+1525
3
Multiple Choice
Simplify.
(x2+1)−(3x+5)
x2+3x+6
x2−3x−4
3x3+5x2+3x+5
3x+5x2+1
x−35+9x+1525
4
Multiple Choice
Simplify.
(x2+1)(3x+5)
x2+3x+6
x2−3x−4
3x3+5x2+3x+5
3x+5x2+1
x−35+9x+1525
5
Multiple Select
Simplify.
(x2+1)÷(3x+5)
x2+3x+6
x2−3x−4
3x3+5x2+3x+5
3x+5x2+1
x−35+9x+1525
6
(f+g)(x) = f(x) + g(x)
= (x2 + 12) + (3x - 7)
= x2 + 12 + 3x - 7
= x2 + 3x + 12 - 7
(f+g)(x) = x2 + 3x + 5
Given f(x) = x2 + 12 and
g(x) = 3x - 7, find
(f+g)(x) = f(x) + g(x)
This simply means to add the two functions and combine like terms.
Addition:
Adding and Subtracting Functions
Please take notes on the above information.
7
(f-g)(x) = f(x) - g(x)
= (x2 + 12) - (3x - 7)
= (x2 + 12) +(-3x + 7)
= x2 + 12 - 3x + 7
= x2 - 3x + 12 + 7
(f+g)(x) = x2 - 3x + 19
Given f(x) = x2 + 12 and
g(x) = 3x - 7, find
(f-g)(x) = f(x) - g(x)
For subtraction, change the signs of each term in the functions, Then combine like terms.
Subtraction:
Adding and Subtracting Functions
Please take notes on the above information.
8
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10
(f⋅g)(x)= f(x) ⋅ g(x)
= (x2 -3x - 40)(x + 5)
= x2(x+5) - 3x(x+5) - 40(x+5)
= x3 +5x2 -3x2 +15x -40x -200
= x3 - 2x2 - 25x - 200
(f⋅g)(x) = x3 - 2x2 - 25x -200
Given f(x) = x2 - 3x - 40 and
g(x) = x + 5, find
(f⋅g)(x) = f(x) ⋅ g(x)
For multiplication, multiply each term in the first function by each term in the second function (F.O.I.L). Then combine like terms.
Multiply:
Multiply and Divide Functions
Please take notes on the above information.
11
(f/g)(x)= f(x)/g(x)
= (x2 - 3x - 40)/(x + 5)
= (x2 - 3x - 40)÷(x + 5)
-5| 1 -3 -40
_____-5___40_
1 -8 | 0
(f/g)(x) = x - 8
Given f(x) = x2 - 3x - 40 and
g(x) = x + 5, find
(f/g)(x) = f(x)/g(x)
For division, make a fraction with one of the functions over the other. You can use synthetic division to divide the numberator by the denomiator.
Divide:
Multiply and Divide Functions
Please take notes on the above information.
12
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14
Example 1
(f⋄g)(x) = f[g(x)]
= 3( ) - 12
= 3(10x) - 12
= 30x - 12
(f⋄g)(x) = 30x - 12
Given f(x) = 3x - 12 and
g(x) = 10x find
(f⋄g)(x) = f[g(x)]
For the composition, start by writing the first function, with an open set of parenthesis instead of the variable. In the paraenthsis, write the other function.
Composition:
Composition of Functions
Please take notes on the above information.
15
Example 2
(g⋄f)(x) = g[f(x)]
= 10( )
= 10(3x - 12)
= 30x - 120
(g⋄f)(x) = 30x - 120
Given f(x) = 3x - 12 and
g(x) = 10x find
(g⋄f)(x) = g[f(x)]
This is the same as Example 1, but you start with second function and you plug in the first equation.
Composition:
Composition of Functions
Please take notes on the above information.
16
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17
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Advanced Algebra,
10.1 Operations and Composition
By Jeremy Adelmann
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