
Trigonometría 1
Presentation
•
Mathematics
•
11th Grade
•
Practice Problem
•
Medium
Ana Pérez
Used 4+ times
FREE Resource
4 Slides • 7 Questions
1
By Ana Pérez
2
Multiple Select
Indica en que cuadrantes el sen α es negativo.
(Más de una solución)
(2 min)
1er cuadrante
2º cuadrante
3 er cuadrante
4º cuadrante
2º y 3er cuadrante
3
4
Multiple Choice
Calcula sen 235º en función del seno de un ángulo del 1.er cuadrante.
(20 seg)
sen 235= sen 55
sen 235= - sen 35
sen 235= -sen 55
sen 235= -sen 145
sen 235= sen -55
5
6
Multiple Choice
Calcula cos 312º en función del seno de un ángulo del 1.er cuadrante.
(20 seg)
cos 312= cos 48
cos 312= cos 130
cos 312= -cos 48
cos 312= cos 4
cos 312= cos - 48
7
Multiple Choice
Calcula en función de un ángulo del 1.er cuadrante.
Observa el
ejemplo e indica la frase correcta para el cos 985°.
(15 min)
cos 985° =
cos 265° =
−cos 85° =
cos 985° =
cos 625° =
cos 85° =
cos 985° =
cos 265° =
−cos 85° =
cos 985° =
cos 265° =
cos 85° =
cos 985° =
sen 115° =
sen 65°
8
Multiple Choice
sen 475° =
sen 165° =
- sen 65°
sen 475° =
sen 295° =
sen -65°
sen 475° =
sen -115º =
sen 65°
sen 475° =
sen 115° =
- sen 65°
sen 475° =
sen 115° =
sen 65°
9
10
Multiple Choice
Calcula tg 1.215° en función del seno de un ángulo del 1.er cuadrante.
(30 seg)
tg 1.215° =tg 225°
tg 1.215° =−tg 45°
tg 1.215° =tg 45°
tg 1.215° =tg -45°
tg 1.215° =tg 145°
11
Multiple Select
Observa el siguiente video e indica las respuestas correctas (Hay más de una):
https://www.youtube.com/watch?v=3WRJpoQQc5M
15 min
sen α =cos β
Si α+β=90
cos 14º = sen 76º
cos 14º = cos 76º
sen14º = sen 76º
By Ana Pérez
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