
Lecture 9.2 - Solve Quadratic Functions by Graphing
Presentation
•
Mathematics
•
6th - 12th Grade
•
Medium
+2
Standards-aligned
Gabe Geering
Used 12+ times
FREE Resource
8 Slides • 16 Questions
1
Lecture 9.2 - Solve Quadratic Functions by Graphing
G2
2
Solve what, bruh?
Solutions to quadratic equations
Solving a quadratic equation means finding solutions that make the equation true. We can do that by setting the function equal to 0, but we can also find solutions by analyzing graphs and finding where y=0.
Are you down with the ZPP?
3
seriously, Solve what, bruh?
methods to solving quadratic equations
Factoring using the Zero Product Property
Square Root Method (only works when a variable squared can be isolated)
Graphing - find where the parabola crosses the x-axis
yeah, we're about to do this
Yeah, you know me.
4
Fr, seriously, Solve what, bruh?
Solution scenarios for quadratic equations
two real solutions
How would you describe the vertex location in each scenario?
no real solutions
one real solution
5
Multiple Choice
6
Multiple Choice
7
Multiple Choice
Determine the solutions of the graph:
No Solutions
(-3, 0) and (-1, 0)
Infinity Many Solutions
(-1, 0)
8
Multiple Choice
What are the solutions?
x=4
x= 0
y=-4
There are no real solutions
9
Multiple Choice
How many solutions are there?
0
1
2
3
10
Multiple Choice
What are the solutions?
x=4
x= 0
y=-4
There are no real solutions
11
Multiple Choice
12
Multiple Choice
What are the zeros of the function in the graph?
(-1, 0) and (1, 0)
(0, -1) and (0, 1)
(0, -1)
(-1, 0) and (1, 0) and (0, -1)
13
Multiple Select
To solve a quadratic by graphing is to find where the parabola crosses the x-axis. We call these the ___. Select all that apply.
zeros
x-intercepts
solutions
roots
14
What if it's already solved, bruh?
writing equations given the solution(s) and another point
To write the equation, a graph with root(s) and one other point is required or simply 2 roots and 1 point as ordered pairs.
15
16
Multiple Choice
Write the equation of the quadratic function that has a x-intercepts at (2, 0) and (4, 0) and passes through the point (3, 4).
y = -4(x - 2)(x - 4)
y = -4(x + 2)(x + 4)
y = 4(x - 2)(x - 4)
y = -0.25(x - 2)(x - 4)
17
Multiple Choice
18
Multiple Choice
What is the equation of the parabola?
y =(x - 1)(x-3)
y = -1/2(x - 1)(x + 3)
y = 2(x + 1)(x - 3)
y = - 1(x- 1)(x - 3)
19
Multiple Choice
20
What if it's already in factored form, bruh?
converting factored form to standard form
Once we've written an equation in factored form, we can expand it to standard form. Other terms you may have heard instead of "expand":
double distribute
FOIL
simplify
reverse factor
Don't forget to distribute the 'a' value!
21
22
Multiple Choice
Rewrite in standard form: y=(x+2)(x+3)
y=2x+5
y=x2+6
y=x2+x+6
y=x2+5x+6
23
Multiple Choice
Rewrite in standard form: y=2(x−3)(x+5)
y=x2+2x−15
y=2x2−30
y=2x2+2x−15
y=2x2+4x−30
24
Multiple Choice
Go from factored to standard form (x+8)(3x−2)
3x2+22x−16
3x2+26x−16
3x2+22x+6
8x⋅−6x
Lecture 9.2 - Solve Quadratic Functions by Graphing
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