Formative 11.1 AMI review

h =4

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(7)(4)=28

28 divided by 2 = 14

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Area = 14 sq. meters​

​Formula

A = (b)(h)

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We only divide by 2 for triangles! ​

h = 4

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(7)(4) = 28

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Area = 28 sq. units. ​

​The total height for the shape is 5 M.

I am given a portion of that high as 2.5.

That leaves the remaining missing height to be 2.5. ​

​The total lengh for the shape is 9M .

I am given a portion of that lengh as 2.5M.

That leaves the remaining missing length to be 6.5 M.​

​The total height for the shape is 5 M.

I am given a portion of that high as 2.5.

That leaves the remaining missing height to be 2.5. ​

​The total lengh for the shape is 9M .

I am given a portion of that lengh as 2.5M.

That leave the remaining missing length to be 6.5 M.​

​The verticle triangle has a base of 2.5 and a hight of 5.

Area = (2.5)(5)

A = ​12.5

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The horizontal triangle has a base of 6.5 and a height of 2.5

Area = (6.5)(2.5)

Area = 16.25​

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Total Area = 12.5 + 16.25

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Final answer = ​28.75 sq. M.

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​We are missing the base and the height of the triangle. We must find these dimensions to calculate the area.

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​The horizontal dotted line and the 5 ft piece must = 11 ft. together.

11 ft - 5 ft = 6ft as my missing triangle base.

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The verticle dotted line (8ft) and the height of our triangle must = 12 ft together. 12 - 8 = 4ft as my missing triangle height.

​The rectangle on the right has a base of 7 and a height of 12.

Area = (b)(h)

Area = (7)(12 = 84 sq ft​

​The rectangle in the middle has a base of 11 and a height of 8.

Area = (b)(h)

Area = (11)(8) = 88 sq. ft​

​The triangle has a base of 6 and a height of 4.

Area = (b)(h) divided by 2.

Area = (6)(4) divided by 2 = 12 sq ft.

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Total Area = 184 sq. feet​