Resistors in Series and Parallel
Presentation
•
Physics
•
11th - 12th Grade
•
Practice Problem
•
Medium
Standards-aligned
Rachel Wampler
Used 18+ times
FREE Resource
7 Slides • 5 Questions
1
By Rachel Wampler
2
Circuit forms one "loop"
Multiple devices in the circuit
Same current through each device
A break in the loop means no more flowing current
The resisters divide the voltage between them
3
Voltage Divide Among Resistors
4
Multiple Choice
A 5.17 kΩ reistor and a 10.09 kΩ resistor are connected in series.
What is the equivalent resistance?
52.17 kΩ
15.26 kΩ
4.92 kΩ
1.95 kΩ
5
Multiple Choice
Bathroom vanity lights are occasionally wired in series. V=120V and you install three bulbs with R=8Ω and one bulb with R=12Ω. what is the current, voltage of each bulb, and the total power?
I = 3.33 A
V = 26.7 V , 40 V
P = 400 W
I = 5 A
V = 40 V, 60 V
P = 900 W
I = 10 A
V = 80 V, 120 V
P = 3600 W
I = 2880 A
V =23 kV, 35 kV
P = 299 MW
6
The same voltage across several devices
Houses are typically wired in parallel
A fault in a device has no effect on current
Resistors divide current
7
Parallel Derivation
8
Parallel Formula Derivation
9
Multiple Choice
A 1000 Ω resistor and 101 Ω resistor are connected in parallel. What is the equivalent resistance? If they were connced to a 3 V battery, how much total current would the battery supply? How much current goes through each resistor?
Rp = 91.8 Ω
Itotal = 32.7 mA
I = 3.0mA, 29.7mA
Rp = 1105 Ω
Itotal = 32.7 mA
I = 3.0mA, 29.7mA
Rp = 91.8 Ω
Itotal = 32.7 mA
I = 5.0mA, 29.7mA
Rp = 1105 Ω
Itotal = 32.7 mA
I = 5.0mA, 29.7mA
10
Simplify any series portions of each branch
simplify the parallel circuity of the branches
If necessary simplify remaining series
11
Multiple Choice
find the equivalent resistance and the total current of the following circuit.
R = 15260 Ω
I = 196 mA
R = 13255 Ω
I = 226 mA
R = 100900 Ω
I = 297 mA
R = 14360 Ω
I = 209 mA
12
Multiple Choice
Find the equivalent resistance.
3826.5 Ω
3927 Ω
994.1 Ω
6164.1 Ω
By Rachel Wampler
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