
Exam Review- Fall 2021- Algebra I Day 1
Presentation
•
Mathematics
•
8th - 10th Grade
•
Medium
Katie Argall
Used 1+ times
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22 Slides • 31 Questions
1
by Katie Argall
2
Classifying #s
order of operations
phrases to expressions
properties
expression values
multistep equations
absolute value equations
literal equations
inequalities
3
Multiple Choice
Which statement is NOT true?
Every rational number is a real number.
Every counting number is a whole number.
Every integer is a rational number.
Every decimal number is an irrational number.
4
Multiple Choice
5
Multiple Choice
Classify the number -2.5
Real, rational
Real, rational, integer
Real, irrational
6
Multiple Choice
π
7
Multiple Choice
8
9
Multiple Choice
10
Multiple Choice
(2 + 7 - 1) ÷ 22
11
12
Multiple Choice
Translate: 35 multiplied by the quantity of r plus 45
35(r+45)
35r+45
35⋅r+45
r+4535
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Translating Phrases
14
Multiple Select
Which demonstrates the commutative property? Select all that apply.
8+9=9+8
(4⋅2)3=3(4⋅2)
9−4=4−9
2⋅3⋅5=2⋅5⋅3
8÷4=4÷8
15
Multiple Choice
(4⋅6)⋅5=4⋅(5⋅6) represents what property?
Commutative property of multiplication
identity property of multiplication
associative property of multiplication
zero property of multiplication
16
Multiple Choice
15(1) = 15
17
We use the word Equality when there is an = sign.
18
Multiple Choice
19
Multiple Choice
20
Multiple Choice
21
1 undo addition or subtraction
2 undo multiplication or division
The exception ... a GIANT fraction!!
22
Multiple Choice
What is the absolute value of -5?
|-5| = ?
-5
5
+(-5)
-5 and 5
23
Multiple Choice
Solve for X
|X|=7
X= 7
X= -7
X= 7 and X= -7
No Solution
24
Multiple Choice
Solve for X
|X| = -3
X= 3 and X= -3
X= 3
X= -3
No Solution
25
with review

26
Think of the absolute value equation as a variable when performing operations to get it isolated. Notice we add 10 to both sides then divide both sides by 3 to get |x-2| isolated. Now the problem |x-2| = 7 can be solved like we just learned.
27
Multiple Choice
What would be the correct setup for solving for X?
|X+3| = 5
X+3= 5 and X+3= -5
X+3= 5 ad X-3= 5
X+3= -5 and X-3 = -5
X+3= 5 and -X-3= -5
28
Multiple Choice
Solve for X
2|X+3|+3=1
X= -4 and X= -2
X=2 and X= -2
X=0
No Solution
29
Multiple Choice
Which inequality is represented by the following graph
x < -8
x > -8
x ≥ -8
x ≤ -8
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When graphing your inequality on the number line, the open circle means the number is not included.
When graphing your inequality on the number line, the closed circle means the number is included.
31
Fill in the Blanks
When graphing an inequality on the number line a closed circle means the number is
Type answer...
32
Multiple Choice
2(x−3)+9≥x
x≥−6
x≥15
x≤−3
x≥−3
x≤−6
33
34
Multiple Choice
Look at the Graph. Write the inequality in interval notation.
[-4, -1)
(-4, -1)
(-4, -1]
[-4, -1]
35
Multiple Choice
Solve and graph:
A
B
C
D
36
Multiple Choice
Solve for C
kca+e=s
c=aesk
c=akes
c=ak(s−e)
c=ak(s−e)
37
Any measurement is always positive, including distance. you can't run a negative mile, even if you run it backwards, you still ran the mile.
38
39
You can remove those vertical lines by changing what is inside them to a positive value. Easy enough for constants(numbers) right? try it.
40
Multiple Choice
What is the absolute value of -5?
|-5| = ?
-5
5
+(-5)
-5 and 5
41
Just like solving for A in an equation, we can do the same for |A|. remember that the value inside the absolute value symbols is the distance from 0. So you can see A=5 if we travel 5 places to the right. Notice if we travel 5 places to the left, we arrive at -5. So A can equal both -5 or 5, depending on what direction we travel.
42
So when we solve for a, we see if a=5, then |5| also equals 5. We also see if a= -5 that |-5| = 5. We can see that when taking the absolute value of a variable, we will have 2 answers; the answer for moving right(towards positive numbers) and the answer for moving left(towards negative numbers).
43
If we want to solve this like the one before, would we say Y= 5 or -5??? Let us try and see.
y=5 then |5| = -5. That does not seem right, because |5| = 5 not -5. What about if y= -5 then |-5| = -5, that also is not right, because
|-5| = 5. So y has no solution because an absolute value can never equal a negative number. You try some.
44
Multiple Choice
Solve for X
|X|=7
X= 7
X= -7
X= 7 and X= -7
No Solution
45
Multiple Choice
Solve for X
|X| = -3
X= 3 and X= -3
X= 3
X= -3
No Solution
46
We can apply this process to more advanced absolute value equations.
47
Notice that we have setup two equations. Both equations have the absolute value symbols removed. But one of them has the value switched to a negative. This is how we find out the distance, one going left and one going right from our starting point on a number line. We solve both equations by isolating the variable, just like we have done before. Both equations are solved by adding 5 to both sides. We have our two answers for X; X=7, X=3.
48
Think of the absolute value equation as a variable when performing operations to get it isolated. Notice we add 10 to both sides then divide both sides by 3 to get |x-2| isolated. Now the problem |x-2| = 7 can be solved like we just learned.
49
Since absolute value is always a positive number, we need to make sure that the equation makes since. Notice in the picture as we start isolating the absolute value part that we end up with |x+2| = -2/3.
Since an absolute value can not equal a negative number, there would be no solution. try some,
use paper and pencil as needed.
50
Multiple Choice
What would be the correct setup for solving for X?
|X+3| = 5
X+3= 5 and X+3= -5
X+3= 5 ad X-3= 5
X+3= -5 and X-3 = -5
X+3= 5 and -X-3= -5
51
Multiple Choice
What would be the correct way to write the problem before solving?
2|x-1|-6=4
|x-1|=5
x-1=5
|x-1|=-5
x-1=-5
52
Multiple Choice
Solve for X
2|X+3|+3=1
X= -4 and X= -2
X=2 and X= -2
X=0
No Solution
53
by Katie Argall
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