
Solve a system of equation using Elimination (Day 2)
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Mathematics
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8th - 9th Grade
•
Hard
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Ms. Parsons
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3 Slides • 5 Questions
1
Solve a system of equation using Elimination (Day 2)
by Kristin Parsons
2
Multiple Choice
To solve a system of equation using the Elimination method, you first need to line up the equations so the matching terms are in the same order.
The next step is to__________________?
Get the equation into slope-intercept form.
Get x or y by itself.
Look for the term with the same coefficient and add or subtract.
Substitute the expression in for either x or y.
I have no idea what the next step is.
3
Practice: Solve the System of equation using Elimination / Combination Method.
Look for the term with a coefficient are the same (1y)
2x + 5y = 17
6x – 5y = -9
Combine like terms to eliminate the y term.
Solve for x
Substitute the value for x into the original equation(s) to find the y value.
Enter the solution on the next slide. (x, y)
4
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5
Multiple Choice
Solve the System of Equation
2x - 3y = 23
x + 3y = -20
(3, -7 2/3)
(1, -7)
x = 43
(-7, 1)
6
Multiple Choice
If I want to solve using Elimintion Method what might I do to eliminate the x terms?
2x + 8y = 6
5x + 20y = 15
Multiply the first equation by 5 and the second by 2 to change the x term to 10x for both.
Solve for x in one equation, then substitution the expression with y into the other equaiton
Multiply the y terms to a common multiple of 8 and 20.
Subtract the second equation from the first.
7
Example: Solve using Elimination Method, coefficients are not the same
7x - y = 19 -> 3(7x - y = 19) -> 21x - 3y = 57
2x - 3y = 19 -> -1 ( 2x - 3y= 19) -> -2x + 3y = -19
19x = 38 (divide both sides by 19)
x = 2
7(2) - y = 19
14 - y = 19
- y = 5
y = -5
(2, -5)
8
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Solve a system of equation using Elimination (Day 2)
by Kristin Parsons
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