
Topic 7 lesson
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Physics, Chemistry
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University
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Professor Tomforde
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13 Slides • 3 Questions
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Topic 7 lesson
by Professor Tomforde
2
New vocabulary word!
Isentropic: The entropy of the system remains constant.
Much like "isothermal" and "isobaric"
3
Entropy is a property.
You'll find it in your lookup tables similar to how we have found v, u, and h.
The same rules apply--you can check the phase by determining how the entropy value 's' compares to the sg or sf in the tables.
4
Let's get a sampling of what you need for your homework....
(Question 1 is very similar to Example 7-2)
5
Multiple Choice
What's the specific entropy of saturated liquid R-134a at 120 kPa?
0.09269 kJ/kg-K
0.94789 kJ/kg-K
I don't want to bother looking at my tables; I'll just suffer through HW 7
0.85529 kJ/kg-K
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If you hate tables....
​
7
If it's air
Recall that you can find the enthalpy of air from A-17 using the temperature
(If the temperature doesn't change then neither does the enthalpy)
You might happen to need this for question 2.
8
When do we use what?
Recall that ideal processes are isentropic, meaning s1=s2.
For some of your homework problems, you won't be given enough properties to determine the phase and find the values you're looking for without using this.
Using the entropy gives you the extra puzzle piece.
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Multiple Choice
Steam at a pressure of 300 kPa and an entropy of 7.2699 kJ/kg-K is
a compressed liquid
a saturated mixture
a saturated vapor
a superheated vapor
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That was a superheated vapor!
You could tell because in A-5 for P = 300 kPa, sg = 6.9917 kJ/kg-K.
If s > sg then it's a superheated vapor.
Let's try a trickier one!
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Multiple Choice
The enthalpy of superheated steam at P =300 kPa and s = 7.2699 kJ/kg-K is closest to which of these?
175 C
2800 kJ/kg
2600 kJ/kg
0.634 m3/kg
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You needed A-6 for that one
Go to the heading P = 0.3 MPa and scroll through the s column to find the closest values to 7.2699 kJ/kg-K, then check the h values.
To get a more precise answer, you'd use linear interpolation.
--yes, you probably have a homework question on this....
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How do we know when to use it?
Recall that isentropic devices are the best possible. Some examples:
the minimum velocity exiting a diffuser (the best diffuser generates no entropy!)
the minimum power needed for a compressor (the best compressor generates no entropy)
Anything that explicitly states "isentropic" or "reversible+isothermal."
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Most of your homework
Draw a box, identify energy inputs and outputs and write an energy balance equation....
If you need to hunt down an enthalpy value to plug into this, consider whether you can use the entropy to find it.
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The last question
is a real doozy!
1. draw the control volume for the turbine. Write the energy balance for this control volume. You'll discover you need an enthalpy value!
2. You need to use the entropy to solve for the quality, then use the quality to solve for the enthalpy.
16
Closing thoughts
If you have a pressure that's not in the superheated vapor table, it may be helpful to check the NIST webbook and use their table instead of ours.
Happy Thanksgiving, everyone!
Topic 7 lesson
by Professor Tomforde
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