Conversión de general a canónica- CIRCUNFERENCIA

$$a=1,\ b=-12,\ c=36$$  

$$a=0,\ b=-12,\ c=36$$  

$$a=1,\ b=12,\ c=36$$  

$$\left(\frac{b}{2}\right)^3$$  

$$-\frac{b}{2a}$$  

$$\left(\frac{b}{2}\right)^2$$  

$$\left(-\frac{4}{2}\right)^2=\left(-2\right)^2=4$$  

$$\left(\frac{4}{2}\right)^2=\left(2\right)^2=4$$  

$$\left(\frac{7}{2}\right)^2=\left(3,5\right)^2=12,25$$  

$$\left(x-2\right)^2=4$$  

$$\left(x-2\right)^2=-3$$  

$$\left(x-2\right)^2=7$$  

del x=28 y del y=24

del x=49 y del y=36

del x= 14 y del y=12

$$\left(x+7\right)^2-\left(y-6\right)^2=-75$$  

$$\left(x+7\right)^2+\left(y-6\right)^2=10$$  

$$\left(x-7\right)^2+\left(y+6\right)^2=10$$  

C(5, -2) , r=40

C(-5, 2), r=9

C(5, -2), r=9