$$x\left(x+1\right)+x$$

$$x+2.x+3$$

$$x\left(x-y\right)\left(x+4\right)$$

$$x\left(x+y\right)+2\left(x+y\right)$$

$$\left(x+2y\right)+x\left(x+2y\right)$$  

$$x\left(x+1\right)+2y\left(x+1\right)$$  

$$\left(x+2y\right)x$$  

$$\left(x+2y\right)\left(1+x\right)$$  

Hằng đẳng thức

Nhóm hạng tử

Kết hợp nhóm hạng tử và đặt nhân tử chung

Đặt nhân tử chung

Đặt nhân tử chung kết hợp sử dụng hằng đẳng thức

Đặt nhân tử chung

Sử dụng hằng đẳng thức

Nhóm hạng tử

$$\left(x+y\right)\left(2+2x\right)$$  

$$\left(x+y\right)\left(3x+y\right)$$  

$$\left(x+y\right)\left(1+2x\right)$$  

$$\left(x+y\right)\left(2+x+y\right)$$  

$$xy\left(14+21x+7xy\right)$$  

$$7xy\left(2+3x+xy\right)$$  

$$7\left(2xy+3x^2y+x^2y^2\right)$$  

$$7xy\left(2+3+1\right)$$  

$$\ x\left(x^2-2x+1-y^2\right)$$  

$$x\left[x^2-2x+1+y^2\right]$$  

$$x\left(x-1-y\right)\left(x-1+y\right)$$  

$$x\left(x+1-y\right)\left(x-1+y\right)$$  

$$\left(2x-y\right)\left(1-2x\right)$$  

$$\left(2x-y\right)+5x\left(2x-y\right)$$  

$$\left(2x-y\right)\left(1+5x\right)$$  

$$\left(2x-y\right)\left(1-5x\right)$$

$$\left(2x-1\right)\left(4x^2+2x+1\right)$$  

$$\left(1+2x\right)\left(1-2x+4x^2\right)$$  

$$\left(1-2x\right)\left(1+2x+4x^2\right)$$  

$$\left(1-2x\right)\left(1-2x+4x^2\right)$$  

$$\left(2x-\frac{1}{2}\right)\left(4x^2-x+\frac{1}{4}\right)$$  

$$\left(2x-\frac{1}{2}\right)\left(4x^2+2x+\frac{1}{4}\right)$$  

$$\left(2x-\frac{1}{2}\right)\left(4x^2+x+\frac{1}{4}\right)$$  

$$\left(2x-\frac{1}{2}\right)\left(4x^2+2x+\frac{1}{4}\right)$$  

$$\left(x-4\right)\left(x-2\right)$$  

$$\left(x-4\right)\left(x+2\right)$$  

$$\left(x+4\right)\left(x-2\right)$$  

$$\left(x-4\right)\left(2-x\right)$$  

$$\frac{1}{5}$$  

$$\frac{-1}{5}$$  

$$\frac{1}{5}$$  hoặc  $$\frac{-1}{5}$$  

$$\frac{1}{5}$$  hoặc  $$0$$  

$$x=2$$  

$$x=-2$$  hoặc $$x=1$$  

$$x=2$$  hoặc  $$x=1$$  

$$x=-2$$  hoặc  $$x=-1$$  

700

620

640

630

$$\frac{1}{x}$$

$$\frac{x+1}{x}$$

$$x^2-5$$

$$\frac{x-1}{0}$$

$$x\ne1$$  

$$x=1$$  

$$x\ne0$$  

$$x=0$$  

$$\frac{x-1}{y-x}$$  

$$\frac{1-x}{x-y}$$  

$$\frac{x-1}{x-y}$$  

$$\frac{y-x}{1-x}$$  

$$x^2+8$$  

$$x^2-8$$  

$$x^2+8x$$  

$$x^2-8x$$  

$$\frac{6}{8}$$  

$$\frac{3x}{4y^3}$$  

$$2xy^2$$  

$$\frac{x^2y^2}{xy^5}$$  

$$\frac{3x}{x-y}$$  

$$\frac{x+y}{3x}$$  

$$-\frac{3x}{x+y}$$  

$$\frac{-3x}{x-y}$$  

$$\frac{3y^2}{2x}$$  

$$-\frac{2x^2}{3y}$$  

$$\frac{2x}{3y^2}$$  

$$-\frac{2x}{3y^2}$$  

$$x^2-4$$  

$$3\left(x+2\right)$$  

$$3\left(x-2\right)$$  

$$3\left(x+2\right)\left(x-2\right)$$  

$$\frac{-2x}{x-4}$$  

$$\frac{2x}{x-4}$$  

$$-\frac{2x}{x-4}$$  

$$\frac{2x}{x+4}$$  

$$\frac{x^2}{10y}$$  

$$\frac{2x^2}{5y}$$  

$$\frac{y^2}{10x}$$  

$$\frac{3y^2}{5y}$$  

1-2-3

1-3-2

3-2-1

3-1-2

$$12x^2y^3z$$  

$$12x^2y^2z$$  

$$10x^2y^3z$$  

$$14x^2y^3z$$  

$$12x\left(x-1\right)$$  

$$12x\left(x-1\right)^2$$  

$$12\left(x-1\right)^2$$  

$$12x\left(x+1\right)^2$$  

$$\frac{x+1}{2\left(x+1\right)}$$  

$$\frac{x-1}{2\left(x+1\right)}$$  

$$\frac{x-1}{2\left(x-1\right)}$$  

$$\frac{x+1}{2\left(x-1\right)}$$  

$$\frac{x-y}{xy}$$  

$$\frac{1}{y-x}$$  

$$\frac{1}{x-y}$$  

$$\frac{1}{xy}$$  

$$\frac{3x^2}{2\left(x+2\right)}$$  

$$\frac{3x^2}{2\left(x-2\right)}$$  

$$\frac{3\left(x+2\right)}{2x}$$  

$$\frac{3x}{2\left(x+2\right)}$$