
Advance Algebra with Trigonometry, Section 2-1: Linear Equations in One Variable
Presentation
•
Mathematics
•
12th Grade
•
Practice Problem
•
Medium
Standards-aligned
Jeremy Adelmann
Used 9+ times
FREE Resource
8 Slides • 9 Questions
1
Section 2-1: Linear Equations in One Variable
by Jeremy Adelmann
2
Students will be able to:
Decide whether a number is a solution of a linear equation.
Solve linear equations by using the addition and multiplication properties of equality.
Solve linear equations by using the distributive property.
Solve linear equations with fractions or decimals.
Identify conditional equations, contradictions, and indentities.
3
If the variable in an equation can be replaced with a real number that makes the statment true, the that number is a solution of the equation.
7 is a solution for the equation
An equation is solved by finding its solution set. The solution set for this equation is {7}.
If multiple equations have the same solution set, then they are Equivalent Equations. The solution set is {2}
4
Solve 5x - 3x - 6 = 14 + 8x + 4.
The goal is to isolate the variable on one side of the equation.
Combine Like Terms
Add 6 to both sides
Subtract 8x from both sides
Divide both sides by -6
5
Fill in the Blanks
Solve the equation.
5x+2 = 3x − 6
Type answer...
6
Fill in the Blanks
Solve the equation.
9p+1=7p−9
Type answer...
7
Fill in the Blanks
Solve the equation.
7x −5x +15=x+8
Type answer...
8
Fill in the Blanks
Solve the equation.
2x + 4 −x=4x − 5
Type answer...
9
Step 1: Clear Fractions - Eliminate any fractions by muliplying each side by the least common denominator.
Step 2: Simplify each side separately - Use distributive property to clear parantheses and combine like terms as needed.
Step 3: Isolate the variable terms on one side. Use the addition property to get all terms with variables on one side of the equation and all numbers on the other.
Step 4: Isolate the varaible - Use the multiplication property to get an equation with just the variable (coefficient of 1) on one side.
Step 5: Check - Substitute the proposed solution into the original equation.
10
Solve 2(k - 5) + 3k = k + 6
Since there are no fractions, Step 1 does not apply.
Distributive Property
Multiply
Combine Like Terms
Add 10 to both sides
Subtract k from both sides
Divide both sides by 4
11
Fill in the Blanks
Solve each equation.
3(2t−4)=20−2t
Type answer...
12
Fill in the Blanks
Solve the equation.
2(3−2x)=x−4
Type answer...
13
Fill in the Blanks
Solve the equation.
2(x+4)=−4(x+1)
Type answer...
14
Solve
Start by eliminating the fractions. Multiply both sides by the LCD, 6.
The LCD is 6.
Distributive Property
Multiply;
15
Distributive Property
Multiply
Combine Like Terms
Add 17 to both sides
Combine Like Terms
Divide both sides by 7
16
Fill in the Blanks
Solve the equation.
43x−1+6x+3=3
Type answer...
17
Fill in the Blanks
Solve the equation.
73x+2−5x+4=2
Type answer...
Section 2-1: Linear Equations in One Variable
by Jeremy Adelmann
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