
4.3 a/b/c/d/e/f: Intro to Entropy
Presentation
•
Chemistry, Science
•
11th - 12th Grade
•
Easy
Erin Hannan
Used 22+ times
FREE Resource
11 Slides • 3 Questions
1
Intro to Entropy
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2
Syllabus dot points
a |
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b |
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c |
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d |
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e |
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f |
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3
Entropy
S, unit = J/K
a measure of disorder
the universe tends over time towards disorder/chaotic (2nd Law of Thermodynamics)
measure of how many arrangements with the same energy
we measure entropy change, not entropy directly
4
Predicting entropy changes
As temp increases, entropy increases
States can predict (i.e. solid = least entropy)
More particles within a system increases energy
When a solute dissolves in a solvent, its entropy increases
5
Using predictions:
Determine the change in entropy of the chemical reaction:
CaO(s) + H2O(l) --> Ca(OH)2(s)
- there are 2 mol of reactant particles, and 1 mol of product particles = less disordered = ΔS = negative
- decrease in amount of liquids, and increase in amount of solids = less disordered = ΔS = negative
Therefore, overall the system has ΔS = negative
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Spontaneity of Reactions
spontaneous = occurs without any additional energy
when a spontaneous process occurs, there is an increase in entropy of the universe
we determine whether something is spontaneous by 2 factors: change in enthalpy and change in entropy
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Determining entropy change from standard entropy values
We are given standard entropy data
Similar to heats of formation
ΔS° = ΣS° (products) - ΣS° (reactants)
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Gibbs Free Energy
quantity that helps us determine whether a reaction will be spontaneous
ΔG
The change in GFE is: ΔG = ΔH-TΔS
Combining the effects of enthalpy, entropy and temperature
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Deciphering
if ΔG is < 0 then reaction is spontaneous (exergonic)
if ΔG is > 0 then reaction is non-spontaneous (endergonic)
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Calculating with GFE for spontaneity
State known values
Sub into formula
Answer the q.
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Calculating temp with GFE
GFE formula can be used to determine the minimum temperature at which reactions switch from spontaneous to not spontaneous
sub in everything but T, and have ΔG = 0 (where reaction is neither spontaneous or NS), and will give you the point of low/high temp
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Multiple Choice
Given the change of phase:
CO2(g) —> CO2(s)
As CO2(g) changes to CO2(s), the entropy of the system
decreases
increases
remains the same
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Multiple Choice
1. Given the following information, calculate ΔG0 for the reaction below at 250C: (K = 0C + 273)
SnCl4(l) + 2 H20(l) → SnO2(S) + 4HCl(g),
ΔH0=133.0 kJ and ΔS0 =401.5 J/K
-252.6 kJ
-13.4 kJ
13.4 kJ
252.6 kJ
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